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alisha [4.7K]
3 years ago
13

Can someone help me with this.​

Mathematics
1 answer:
solong [7]3 years ago
7 0
The answer to this question is 8-2.
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What is the difference between a right, acute, and obtuse triangle?
kakasveta [241]

A right triangle has one angle that's 90° and a corner that looks like an L. Obtuse triangles have one angle that's greater than 90°. In acute triangles, all the angles are less than 90°.

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Mrs.Lamb’s favorite candy bar weight 3 ounces. If a box contains 150 of these candy bars, what is the weight, In pounds, of this
Bumek [7]

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28.125

Step-by-step explanation:

A bar weights 3 ounces, she has a box of 150 so you multiply

150 times 3 = 450

well one pound equals 16 ounces, so you divide

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3 years ago
With a family bowling pass, families can bowl for $4 per game . The pass cost $10 per year. Use equation , a table and a graph t
Klio2033 [76]

Answer:

Part a) a=4g+10 (see the explanation)

Part b) see the explanation

Part c) The graph in the attached figure

Step-by-step explanation:

<u><em>The complete question is</em></u>

With a family bowling pass, families can bowl for $4 per game. The pass costs $10 per year. Use an equation, a table, and a graph to explain the relationship between the total amount of money spent on bowling in a year, a, and the number of games a family plays in a year, g. Part A Use words and an equation to represent this problem. Part B Create a table to show values for g and a. Part C Use the values from your table to draw a graph.

Part A) Use words and an equation to represent this problem

Let

a ----> the total amount of money spent on bowling in a year

g ---> the number of games a family plays in a year

we know that

The linear equation in slope intercept form is equal to

a=mg+b

where

m is the slope or unit rate

b is the a-intercept or initial value

In this problem we have

m=\$4\ per\ game

b=\$10

substitute

a=4g+10

Part b) Create a table to show values for g and a

Assume different values of g and calculate the corresponding values of a

For g=0 ----> a=4(0)+10=\$10

For g=1 ----> a=4(1)+10=\$14

For g=2 ----> a=4(2)+10=\$18

For g=3 ----> a=4(3)+10=\$22

For g=4 ----> a=4(4)+10=\$26

The table is

\left[\begin{array}{ccc}g&a\\0&10\\1&14\\2&18\\3&22\\4&26\end{array}\right]

Part c) Use the values from your table to draw a graph

we have the ordered pairs

(0,10),(1,14),(2,18),(3,22),(4,26)

Plot the ordered pairs and join them to graph the line

The graph in the attached figure

6 0
3 years ago
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