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DaniilM [7]
3 years ago
11

What is 2(3x-5) + 3(2x+3)​

Mathematics
2 answers:
kati45 [8]3 years ago
8 0
Work shown
2(3x-5)+3(2x+3)
6x-10+6x+9
12x-1
Karolina [17]3 years ago
7 0

Answer:

12x - 1

Step-by-step explanation:

Distribute the 2 and 3:

2(3x - 5) + 3(2x + 3)​

(6x - 10) + (6x + 9)

Add like terms:

12x - 1

So, the answer is 12x - 1

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Plz help me with this math problem
Leya [2.2K]

Answer:

The answer is B 1/4 + 2/6 + 4/10

Step-by-step explanation:

it just makes sense im sorry i cant explain :( i hope it helps either way xx <3

4 0
3 years ago
Hello someone help me please
stealth61 [152]

Answer:

b

Step-by-step explanation:

4 0
3 years ago
The ratio 20/10=5/n. What does n equal?
DIA [1.3K]
N is equal to 2.5

I divided 20 by 5 to get 4. = 20 ÷ 5 = 4. So, I divide 10 by 4 to get n. = 10 ÷ 4 = 2.5

Or we can do this solution.

20          5
----  =    ----  ; do cross multiplication.  20n = 10(5)
10          n

20n = 50 ; to get n, divide both sides by 20.    20n / 20 = 50 / 20 = n = 2.50

Whichever way: 20/10 = 5/2.5
6 0
4 years ago
Matematicas
Minchanka [31]

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B

Step-by-step explanation: edge

3 0
3 years ago
Z^5=-243i, find the solution to the equation whose argument is strictly between 180 degrees and 270 degrees. Round your answer t
11Alexandr11 [23.1K]

Answer:

The solution is z = -2.853 - i 0.927.

Step-by-step explanation:

Complex power is determined by means of the De Moivre's Theorem, whose expression is:

z^{n} = r^{n} \cdot (\cos n\theta + i \sin n\theta)

Where r is the norm of the complex number. In this case, expression can be written as:

-i 243 = 3^{5} \cdot (\cos 5\theta + i \sin 5\theta)

The real component must be equal to zero and complex component must be equal to -1. That is to say:

\cos 5\theta = 0

\sin 5\theta = -1

Possible solutions for each component are, respectively:

Real component

5\theta = \cos^{-1}0

5\theta = \frac{\pi}{2} \pm \pi\cdot j, \forall j \in \mathbb{N}_{O}

\theta = \frac{\pi}{10} \pm \frac{\pi}{5}  \cdot j, \forall j \in \mathbb{N}_{O}

Possible solutions: \frac{11\pi}{10}, \frac{13\pi}{10}, \frac{3\pi}{2}

Complex component

5\theta = \sin^{-1}(-1)

5\theta = \frac{3\pi}{2} \pm 2\pi \cdot j, \forall j \in \mathbb{N}_{O}

\theta = \frac{3\pi}{10} \pm \frac{2\pi}{5}  \cdot j, \forall j \in \mathbb{N}_{O}

Possible solutions: \frac{11\pi}{10}, \frac{3\pi}{2}

There is one solution whose argument is strictly between 180 degrees (\pi) and 270 degrees (1.5\pi).

z = 3 \cdot \left( \cos \frac{11\pi}{10} + i \sin \frac{11\pi}{10} \right)

z = -2.853 - i 0.927

6 0
3 years ago
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