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Yakvenalex [24]
3 years ago
10

Meghan has $1.10 I'm dimes nickels and pennies. She has three times as many nickels as pennies, and the number of dimes is two l

ess than the of pennies. how many dimes nickels and pennies does she have?
Mathematics
1 answer:
Dmitriy789 [7]3 years ago
7 0
N=3p and d=p-2  we are also told that:

p+n+d=110 using n and d from above we get:

p+3p+p-2=110

5p-2=110

5p=112

p=112/5

Which is not an integer...are we sure there is no typo in the question...

There are 3 times as many nickels as pennies

There are pennies-2 dimes 

And the total is $1.10

Just checking, because something is off...
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The relative frequency of selecting a diamond from 40 trials of selecting a random card is 30%.

<h3>What is relative frequency?</h3>

The relative frequency of an event is the ratio of total number of favorable or desired outcome to the total number of trails done.

Given information-

The card is selected random from the deck of cards.

Total number of trails is 40.

It is known that the total number of diamond card in a standard deck of card is 11. There is total 40 trials is done in which a random card is selected.

As the relative frequency is the ratio of total number of diamonds to the total number of trials done. Thus,

f_r=\dfrac{11}{40}\\f_r=0.3

In the percentage from,

f_r={0.3}\times100\\f_r=30

Thus the relative frequency of selecting a diamond from 40 trials of selecting a random card is 30%.

Learn more about the relative frequency here;

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2 years ago
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3 years ago
Multiply each equation by a constant that would help to eliminate the y terms.
Zinaida [17]

Answer:

Therefore the required resulting equation is

6x-15y=-63\\-15x+15y=90

6 x minus 15 y = negative 63.

Negative 15 x + 15 y = 90

Step-by-step explanation:

Given:

2x-5y=-21         ......................Equation ( 1 )

3x-3y=-18         ......................Equation ( 2 )

To Find:

Expression after multiplying to eliminate y term,

Solution:

So to eliminate 'y' term we need to multiply equation 1 by a constant 3 and equation 2 by a constant -5,  such that equations  becomes

3(2x-5y)=3\times -21\\\\6x-15y=-63 .....( 1 )

-5(3x-3y)=-5\times -18\\\\-15x+15y=90  .....( 2 )

so now by adding new equation one and two we can eliminate y term that means -15y and +15y will get cancel,

Therefore the required resulting equation is

6x-15y=-63\\-15x+15y=90

6 x minus 15 y = negative 63.

Negative 15 x + 15 y = 90

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3 years ago
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