Does anyone know the correct answer?

Hector, Sam, Ted, and Gina are comparing their savings. Hector saved twice as much money as Sam. Ted saved $100 more than Hector

lutik1710 [3]

Answer:

$2x+50$

Step-by-step explanation:

Given: Hector saved twice as much money as Sam.

Ted saved $100 more than Hector.

Gina saved $50 less than Ted.

As given, lets assume the amount of money Sam has in saving be "x".

Now, finding saving of each person given.

Writing the algebric expression of each´s saving amount.

we know, Hector saved twice as much money as Sam.

∴ Hector saving= $\$2x$

Also, Ted saved $100 more than Hector.

∴ Ted´s saving= $\$(2x+100)$

Next finding Gina´s saving

As given, Gina saved $50 less than Ted.

∴ Gina´s saving= $\$ (2x+100)-\$ 50$

Opening parenthesis and solving it.

⇒ Gina´s saving= $\$ 2x+\$50$

Algebric expression of Gina´s saving= $2x+50$

5 0

3 years ago

In circle O, BC=14 and DC=25. What is the length of diameter BA? -58.6 -12.2 -44.6 -30.6

Savatey [412]

The picture in the attached figure

we know that
If a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment
so
DC²=BC*CA-----> CA=DC²/BC
DC=25
BC=14
CA=25²/14-----> CA=44.64
CA=BC+BA----> BA=CA-BC----> BA=44.64-14----> BA=30.64

BA is the diameter
hence
the length of diameter BA is 30.64----> round to the nearest tenth---> 30.6

the answer is
the length of diameter BA is 30.6

7 0

3 years ago

Solve the equation 3 . 10^4 = 3,600

quester [9]

The solution is false!
3.1 would become a fraction that will be calculated back into a decimal by the 4th power making it 92.3521=3,600.. so the equality is false because the left hand and the right hand side are different.

8 0

2 years ago

Plz help!

Marizza181 [45]

Answer:

800 is the answer

Step-by-step explanation:

90-40= 50---->4000/50=800

4 0

3 years ago

MATH HELP PLEASE 50 POINTS:

Delicious77 [7]

Answer:

$f(x)=-a(x+2)(2x-1)(x-3)$ where a>0.

To graph the the polynomial, begin in the left top of quadrant 2. Then draw downwards to the first real zero on the x-axis at -2. Cross the x-axis and then curve back up to 1/2 on the x-axis. Cross through again and curve back down to cross for the last time at 3 on the x-axis. The graph then ends going down towards the right in quadrant 4. It forms an s shape.

Step-by-step explanation:

The real zeros are the result of setting each factor of the polynomial to zero. By reversing this process, we find:

zero -2 is factor (x+2)

zero 1/2 is factor (2x-1)

zero 3 is factor (x-3)

We write them together with an unknown leading coefficient a which is negative so -a.

$f(x)=-a(x+2)(2x-1)(x-3)$ where a>0

The leading coefficient of a polynomial determines the direction of the graph's end behavior.

A positive leading coefficient has the end behavior point up when an even degree and point opposite directions when an odd degree with the left down and the right up.

A negative leading coefficient has the end behavior point down when an even degree and point opposite directions when an odd degree with the left up and the right down.

This graph has all odd multiplicity. The graph will cross through the x-axis each time at its real zeros.

To graph the the polynomial, begin in the left top of quadrant 2. Then draw downwards to the first real zero on the x-axis at -2. Cross the x-axis and then curve back up to 1/2 on the x-axis. Cross through again and curve back down to cross for the last time at 3 on the x-axis. The graph then ends going down towards the right in quadrant 4. It forms an s shape.

4 0

3 years ago