Question

The normal lead content in human blood is about 0.40 ppm (parts per million, meaning 0.40 g of lead for each million grams of blood). How much lead would be present in 6.0×103 g of blood?

Answer 1

Answer:

Lead in $6.0 * 10^{3}$g of blood $= 2.4 * 10^{-3}$grams

Explanation:

Given -

Amount of lead in human blood - $0.40$ parts per million (ppm)

This is equivalent to $0.40$ g of lead for each million grams of blood

Numerically, it can be represented as -

$\frac{0.40}{1*10^6} \frac{g}{million gram}$

Lead in $6.0 * 10^{3}$g of blood

$= \frac{0.40}{10^6} * 6.0 * 10^3\\= 2.4 * 10^{-3}$ grams

Lead in $6.0 * 10^{3}$g of blood $= 2.4 * 10^{-3}$grams

Answer 2

Answer:

$2.4x10^{-3}$

Explanation:

We can solve this equation in a lot of different ways, the easiest equation is called ruled of three, and it's solved as follows:

$1000000g/0.40g = 6(10)^{3} /x$ this is an equality of the information that has been given to us, and we solve it algebraically.

X = How much lead would be present in 6.0×103 g of blood

$x (1000000)g/0.40g =6(10)^{3}g$

$x=6(10)^{3}g 0.40g/1000000g=2.4x10^{-3}g$

And that's how we conclude the lead content in 6*10^3g blood