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3 years ago

Convert 4/3 to an mixed number

Mathematics

1 answer:

wariber [46]3 years ago

4 0

1 1/3. One whole number is 3/3 so 3/3=1 then u put 1/3

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The sum of the ages of Jeremy and Kimberly is 64 years. 8 years ago, Jeremy's age was 2 times Kimberly's age. How old is Jeremy

TiliK225 [7]

Answer:

36.666 (The six keeps going)

Step-by-step explanation:

In this question you'll be trying to find out what x is.

(x-8), this is from the amount of years ago and 2(56-x) is from subtracting 8 with 64 and the 2 came from the fact that Jeremy is twice the age.

(x-8)=2(56-x)

x-8=102-2x

Now we want to have x by itself so we'll add 2x on both sides to remove the -2x from the right side.

3x-8=102 (Add up on both sides)

3x=110 (Divide by 3)

x=36.666

4 0

3 years ago

Which problem situation could the equation below represent? 164/x = 8 (x ≠0)

Gelneren [198K]

Answer:

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Verify cot x sec^4x=cotx +2tanx +tan^3x

Tanzania [10]

Answer:

See explanation

Step-by-step explanation:

We want to verify that:

$\cot(x) \: { \sec}^{4} x = \cot(x) + 2 \tan(x) + { \tan}^{3} x$

Verifying from left, we have

$\cot(x) \: { \sec}^{4} x = \cot(x) \: ( 1 + { \tan}^{2} x )^{2}$

Expand the perfect square in the right:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: ( 1 + { 2\tan}^{2} x + { \tan}^{4} x)$

We expand to get:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: + \cot(x){ 2\tan}^{2} x +\cot(x) { \tan}^{4} x$

We simplify to get:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: + 2 \frac{ \cos(x) }{\sin(x) ) } \times \frac{{ \sin}^{2} x}{{ \cos}^{2} x} +\frac{ \cos(x) }{\sin(x) ) } \times \frac{{ \sin}^{4} x}{{ \cos}^{4} x}$

Cancel common factors:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: + 2 \frac{{ \sin}x}{{ \cos}x} +\frac{{ \sin}^{3} x}{{ \cos}^{3} x}$

This finally gives:

$\cot(x) \: { \sec}^{4} x = \cot(x) + 2 \tan(x) + { \tan}^{3} x$

3 0

3 years ago

Will's company offers a reimbursement package of $0.59 per mile plus $275

rodikova [14]

Answer:

D. C = 0.59x+ 275

Step-by-step explanation:

6 0

2 years ago

If sin(x) = 5/13, and x is in quadrant 1, then tan(x/2) equals what?

Rufina [12.5K]

$x$ is in quadrant I, so $0$ , which means $0$ , so $\dfrac x2$ belongs to the same quadrant.

Now,

$\tan^2\dfrac x2=\dfrac{\sin^2\frac x2}{\cos^2\frac x2}=\dfrac{\frac{1-\cos x}2}{\frac{1+\cos x}2}=\dfrac{1-\cos x}{1+\cos x}$

Since $\sin x=\dfrac5{13}$ , it follows that

$\cos^2x=1-\sin^2x\implies \cos x=\pm\sqrt{1-\left(\dfrac5{13}\right)^2}=\pm\dfrac{12}{13}$

Since $x$ belongs to the first quadrant, you take the positive root ( $\cos x>0$ for $x$ in quadrant I). Then

$\tan\dfrac x2=\pm\sqrt{\dfrac{1-\frac{12}{13}}{1+\frac{12}{13}}}$

$\tan x$ is also positive for $x$ in quadrant I, so you take the positive root again. You're left with

$\tan\dfrac x2=\dfrac15$

4 0

3 years ago