Answer: The required width of the park is 3 miles.
Step-by-step explanation: Given that a 5 mile jogging path diagonal divides a rectangular park in half and the park is 4 miles long.
We are to find the width of the park.
As shown in the attached figure below, the diagonal BD divides the rectangle ABCD into two equal parts,
where length DA = 5 miles, BD = 4 miles and AB = width = ?
Since each angle of a rectangle is right-angle, so triangle ABD will be a right-angled triangle.
Using Pythagoras theorem in triangle ABD, we have
Thus, the required width of the park is 3 miles.
The inequality begins with the flat fee of $25. We then add the $13 per day for insurance as 13<em>d</em>, where <em>d</em> is the number of days. This gives us the expression
25 + 13<em>d</em>. Since he only has $121, we must use less than or equal to for our inequality; he can't spend any more than $121, but he can spend any number below it up to that number. This gives us
25 + 13<em>d</em> ≤ 121<em />
I only know 1 & 4 .. 2 & 3 seem hard to me ..
X >7
X< -7
-
He will be making a right triangle with the legs being 24 x 45. The diagonal will be the hypotenuse of the triangle. To find the amount of fencing we need the perimeter of the triangle.
Use Pythagorean theorem to find the length of the hypotenuse.
a^2 + b^2 = c^2
24^2 + 45^2 = c^2
576 + 2025 = c^2
2601 = c^2
sqrt 2601 = c
c = 51
Adding the three lengths the total fencing needed is
51+24+45=120 meters
Answer:
4:!
Step-by-step explanation:
4:1 because their are 4 boys for every 1 girl
