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sattari [20]
3 years ago
14

Which of the following equations correctly represents the law of cosines?

Mathematics
1 answer:
dusya [7]3 years ago
7 0

Answer:

C

Step-by-step explanation:

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A gardener buys a rake and a pair of gloves for each of the 12 volunteers in the gardening club. Each pair of gloves
matrenka [14]

Let unit cost of one rake be : r

Given : Total number of volunteers = 12

Given : Each pair of gloves cost $8.00

⇒   Cost of 12 pair of gloves for 12 volunteers = (12 × 8) = $96

Given : The gardener spends a total of $300 on both rakes and gloves

⇒   Cost of 12 rakes + Cost of 12 pair of gloves = $300

⇒   12r + 96 = 300

⇒   12r = 204

⇒   r = 17

<u>Answer</u> : Cost of one rake is $17

4 0
3 years ago
What percent of 18.75 is 27?
Olin [163]
The answer is 144%





Your welcome

4 0
3 years ago
Please help me out<br><br><br><br> Find the area .
Gemiola [76]

Answer:

its27.54 8.1×3.4 =27.54 base×height

7 0
3 years ago
Im confused and i need help please help
denis23 [38]

Answer:

C

Step-by-step explanation:

8 0
3 years ago
Which set of numbers could represent the lengths of the sides of a right triangle?
DiKsa [7]

Answer:

The first set: 8, 15, and 17.

Step-by-step explanation:

<h3>Pair: 8, 15, 17</h3>

By the pythagorean theorem, a triangle is a right triangle if and only if

\text{longest side}^2 = \text{first shorter side}^2 + \text{second shorter side}^2.

In this case,

\text{longest side}^2 = 17^2 = 289.

\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 8^2 + 15^2\\ &=64 + 225 = 289 \end{aligned}.

In other words, indeed \text{hypotenuse}^2 = \text{first leg}^2 + \text{second leg}^2. Hence, 8, 15, 17 does form a right triangle.

Similarly, check the other pairs. Keep in mind that the square of the longest side should be equal to the sum of the square of the two

<h3>Pair: 10, 15, 20</h3>

Factor out the common factor 2 to simplify the calculations.

\text{longest side}^2 = 20^2 = 400

\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 10^2 + 15^2\\ &=100 + 225 = 325 \end{aligned}.

\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2.

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

<h3>Pair: 12, 18, 22</h3>

\text{longest side}^2 = (2\times 11)^2 = 2^2 \times 121.

\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= (2 \times 6)^2 + (2 \times 9)^2\\ &=2^2 \times(36 + 81) = 2^2 \times 117 \end{aligned}.

\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2.

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

<h3>Pair: 7, 9, 11</h3>

\text{longest side}^2 = 11^2 = 121.

<h3>\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 7^2 + 9^2\\ &=49+ 81 = 130 \end{aligned}.</h3>

\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2.

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

6 0
3 years ago
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