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3 years ago

What is the simplified form of sqrt(72x^16/50x^36 assume x does not =0

Mathematics

1 answer:

love history [14]3 years ago

8 0

Answer:

the correct answer is A

6/5x^10

Step-by-step explanation:

You might be interested in

Plutonium-240 decays according to the function L where o

PIT_PIT [208]

Answer:

$\boxed{\textbf{1700 yr}}$

Step-by-step explanation:

$-\dfrac{\text{d}L}{\text{d}t} = kL\\\\\dfrac{dL}{L}=-kdt\\\\\ln L = -kt + C\\\text{At t = 0, L = L$_{0}$, so C = $\ln L_{0}$}\\\ln L = -kt + \ln L_{0}\\\ln L_{0} - \ln L = kt\\\\\ln \dfrac{L_{0}}{L} =kt$

Data:

L₀ = 24 g

L = 20 g

k = 0.000 11 yr⁻¹

Calculation:

$\ln \dfrac{24}{20} =0.000 11t\\\\\ln 1.2 = 0.000 11t\\\\0.1823 = 0.000 11t\\\\t = \dfrac{0.1823}{0.000 11} = \textbf{1700 yr}\\\\\text{It will take } \boxed{\textbf{1700 yr}}\text{ for the polonium to decay to 20 g}$

8 0

3 years ago

What are three terms in the sequence 4096, 1024, 256, 64

mash [69]

If you mean 3 more terms in the sequence they could be

64, 32, 16, 8 ...

If you mean any 3 terms then 4096 1024 and 256 qualify.

6 0

3 years ago

Read 2 more answers

5000 containers are stacked 20 wide and 50 long on a ship. How many containers high are they? Pls answer and give explanation, t

shutvik [7]

Answer:

5 containers high

Step-by-step explanation:

Given that :

Given :

Width = 20 containers

Length = 50 containers

Total containers = 5000

Hence,

Total containers = width * length * height

5000 = 20 * 50 * height

5000 = 1000 * height

Height = 5000 / 1000

Height = 5 containers

3 0

2 years ago

1.Arsenic-74 is used to locate brain tumors. It has a half-life of 17.5 days. 90 mg wereused in a procedure. Write an equation t

Sophie [7]

$1)\text{ }N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}$

2) 5.625 mg will be left

Explanation:

1) Half-life = 17.5 days

initial amount of Arsenic-74 = 90 mg

To get the equation, we will use the equation of half-life:

$\begin{gathered} N_t\text{ = N}_0(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}} \\ where\text{ N}_t\text{ = amount remaining} \\ N_0\text{ = initial amount} \\ t_{\frac{1}{2}\text{ }}\text{ = half-life} \end{gathered}$ $N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}$

2) we need to find the remaining amount of Arsenic-74 after 70 days

t = 70

$\begin{gathered} N_t=\text{ 90\lparen}\frac{1}{2})^{\frac{70}{17.5}} \\ N_t\text{ = 5.625 mg} \end{gathered}$

So after 70 days, 5.625 mg will be left

4 0

1 year ago

Carrie missed 9.6% of the problems on a test. The test had a total of 125 problems.

Nataly_w [17]

Answer:

G 13

Step-by-step explanation:

X/125 = 9.6%/100%

125*(9.6) / 100 = 12;

BEST estimate 13

7 0

2 years ago