The right answer is Option D.
Step-by-step explanation:
Let,
Kyle's money = x
Hayden's money = y
Jeremy's money = z
According to statements;
Kyle has three times as much money in his savings account as Hayden.
x = 3y Eqn 1
Hayden has twice as much money in his savings account as Jeremy.
z = 2y Eqn 2
Combined Kyle, Hayden, and Jeremy have a total of $612.
x+y+z=612 Eqn 3
Putting value of x and z from Eqn 1 and 2 in Eqn 3
![3y+y+2y=612\\6y=612](https://tex.z-dn.net/?f=3y%2By%2B2y%3D612%5C%5C6y%3D612)
Dividing both sides by 6
![\frac{6y}{6}=\frac{612}{6}\\y=102](https://tex.z-dn.net/?f=%5Cfrac%7B6y%7D%7B6%7D%3D%5Cfrac%7B612%7D%7B6%7D%5C%5Cy%3D102)
Putting in Eqn 1;
![x=3(102)\\x=306](https://tex.z-dn.net/?f=x%3D3%28102%29%5C%5Cx%3D306)
Kyle has $306 in his account.
The right answer is Option D.
Keywords: Linear equations, division
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