I'm guessing the equation is 2x^2-3x=-5
If this is the case, then you need to set the equation to equal 0 by moving the -5 to the left side of it
2x^2-3x+5=0
The you can factor the equation
(2x-5)(x+1)=0
now solve for each factor
2x-5=0 is x=5/2x
x+1=0 is x=-1
Answer:
This is your answer If I'm right so.
Please mark me as brainliest. thanks!!
Answer:
f(2) = 1
(1) = 2
(f(2)) = 2
Step-by-step explanation:
f(x) = x
(x) = 2x
f(2) = (2)
f(2) = 1
(1) = 2(1)
(1) = 2
(f(2)) = 2((2))
(f(2)) = 2(1)
(f(2)) = 2
Remove parentheses by multiplying factors.use exponent rules to remove parentheses in terms with exponents.combine like terms by adding coefficients.combine the constants
Answer:
Step-by-step explanation:
Domain x^2 - 9 {Solution: - infinity < x < infinity}
Interval notation (- infinity, infinity)
Range of x^2 - 9 (Solution: f(x) is greater than or equal to - 9)
Interval notation (-9, infinity)
Axis interception points of x^2 - 9:
X- intercepts (3, 0) (-3, 0)
Y-intercepts (0, -9)
Vertex of x^2 - 9: Minimum (0, -9)
Solve for f:
f (x) = x^2 - 9
Step 1: Divide both sides by x.
fx / x = x^2 - 9 / x
f = x^2 - 9 / x
Answer:
f = x^2 - 9 / x
