Answer:
25
Step-by-step explanation:
Answer:
The dimension of the plot is 30 yd by 20 yd
Step-by-step explanation:
Given;
Area = 600 yd^2
Length = width + 10
l = w + 10 ......1
Area of a rectangular plot is;
Area A = length × width
A = l × w
Substituting equation 1;
A = (w+10) × w
A = w^2 + 10w
600 = w^2 + 10w
w^2 +10w -600 = 0
Solving the quadratic equation;
w = -30 or 20
cannot be negative
w = 20 yd
l = w+10 = 20+10 = 30yd
The dimension of the plot is 30 yd by 20 yd
Answer:
five hundred fifty thousandths
Step-by-step explanation:
Recognize the place value of the rightmost digit, and write the name of the number that ends in that place.
The third place to the right of the decimal point is the <em>thousandths</em> place. The number between that and the decimal point is 550, <em>five hundred fifty</em>.
five hundred fifty thousandths
Answer:
(a) 120 square units (underestimate)
(b) 248 square units
Step-by-step explanation:
<u>(a) left sum</u>
See the attachment for a diagram of the areas being summed (in orange). This is the sum of the first 4 table values for f(x), each multiplied by 2 (the width of the rectangle). Quite clearly, the curve is above the rectangle for the entire interval, so the rectangle area underestimates the area under the curve.
left sum = 2(1 + 5 + 17 + 37) = 2(60) = 120 . . . . square units
<u>(b) right sum</u>
The right sum is the sum of the last 4 table values for f(x), each multiplied by 2 (the width of the rectangle). This sum is ...
right sum = 2(5 +17 + 37 +65) = 2(124) = 248 . . . . square units
To find the average rate of change of given function f(x) on a given interval (a,b):
Find f(b)-f(a), b-a, and then divide your result for f(b)-f(a) by your result for b-a:
f(b) - f(a)
------------
b-a
Here your function is f(x) = x^2 - 2x + 3. Substituting b=5 and a=-2,
f(5) = 5^2 -2(5)+3 =? and f(-2) = (-2)^2 - 2(-2) + 3 = ?
Calculate f(5) - [ f(-2) ]
------------------ using your results, above.
5 - [-2]
Your answer to this, if done correctly, is the "average rate of change of the function f(x) = x^2+2x+3 on the interval [-2,5]."
