Answer:
500 pounds
Step-by-step explanation:
Let the pressure applied to the leverage bar be represented by p
Let the distance from the object be represented by d.
The pressure applied to a leverage bar varies inversely as the distance from the object.
Written mathematically, we have:
Introducing the constant of proportionality
If 150 pounds is required for a distance of 10 inches from the object
Therefore, the relationship between p and d is:
When d=3 Inches
The pressure applied when the distance is 3 inches is 500 pounds.
9514 1404 393
Answer:
AE = CE = 23; BE = DE = 20
Step-by-step explanation:
Put the values of the variables in their place and do the arithmetic.
AE = 2u+5 = 2(9) +5 = 23
BE = 6v-1 = 6(3.5) -1 = 20
CE = 3u-4 = 3(9) -4 = 23
DE = 8v-8 = 8(3.5) -8 = 20
The diagonals cross at their midpoints, so the quadrilateral is a parallelogram.
Answer:
8.06
Step-by-step explanation:
I used my brain and paper. I don't want to have to explain it anymore sorry but yes I think that is the right answer.
Answer:−28−98i
Step-by-step explanation:
Answer:
0.625
Step-by-step explanation:
Just take a calculator and devide it
