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Fynjy0 [20]
3 years ago
14

If a line passes through (2, 4) and (5,-4), what is the slope?​

Mathematics
1 answer:
Mila [183]3 years ago
6 0

Answer:

So the slope is -8/3

Step-by-step explanation:

to find the slope you have to use m = y2-y1/x2-x1

so lets plug in our numbers

m = - 4- 4/5-2

 = -8/3

So the slope is -8/3

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Simplify. Express your answer as a single term using exponents.<br> 960*5x960*9
adelina 88 [10]

{960}^{5}  \times  {960}^{9} \\  =  {960}^{5 + 9}   \\  =  {960}^{14}

<u>Answer</u><u>:</u>

<u>{960}^{14}</u>

<u>Hope </u><u>you</u><u> could</u><u> get</u><u> an</u><u> idea</u><u> from</u><u> here</u><u>.</u>

<u>Doubt</u><u> clarification</u><u> </u><u>-</u><u> </u><u>use </u><u>comment</u><u> section</u><u>.</u>

7 0
2 years ago
Make a table showing all the possible outcomes for spinning the pointer of a spinner with four equal-sized sections labeled 1–4
natka813 [3]

Answer:

12.5%

Step-by-step explanation:

There are two types of spinners here and the outcome of them is independent. That means

P(odd number,C) = P(odd number) * P(C)

There are two odd numbers out of four numbers in the first spinner. The chance of odd number will be:

P(odd) = 2/(2+2)= 1/2= 50%

There are four letters and the desired outcome is C. The chance for C will be:

P(C)= 1/4= 25%

Then the chance will be:

P(odd number,C) = P(odd number) * P(C)

P(odd number,C) =50% * 25% = 12.5%

3 0
3 years ago
Need help asap please​
cestrela7 [59]

Answer:

9:49 is the answer because question say ratio is square of small and big

6 0
2 years ago
Give correct answer please!!!
Anit [1.1K]
The perimeter is 4\frac{16}{13} or 5\frac{3}{13}
3 0
3 years ago
Find the Laplace transformation of each of the following functions. In each case, specify the values of s for which the integral
MAVERICK [17]

Answer:

a. \frac {2} {s-1} converges to s> 1.

b. \frac{3}{e^3 \left(s-5 \right)} converges to s> 5.

c. - \frac {2}{s + 3} converges to s> - 3.

d. \frac {s}{s^2 + 25} converges to s> 0.

e. \frac {10} {s^2 + 1} converges even s> 0.

f. \frac {12}{s^2 + 4} converges to s> 0.

g. -\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4} converges to s> 0.

h. \frac {1} {s ^ 2 + 4} converges to s> 0.

Step-by-step explanation:

a. L \left\{2e^t \right\} = 2L \left\{e^t \right\} = 2 \cdot \frac {1} {s-1} = \frac {2} {s-1} converges to s> 1.

b. L \left\{3e^{5t-3} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = \frac{3}{e^3 \left(s-5 \right)} converges to s> 5.

c. L \left\{-2e^{-3t} \right\} = -2L \left\{e^{-3t} \right\} = - \frac {2}{s + 3} converges to s> - 3.

d. L \left\{\cos\left (5t \right)\right\} = \frac {s}{s^2 + 25} converges to s> 0.

e. L \left\{10 \sin\left(t\right)\right\} = 10L\left\{\sin\left(t\right)\right\} = \frac {10} {s^2 + 1} converges even s> 0.

f. L \left\{6\sin \left(2t \right) \right\} = 6L\left\{\sin\left (2t\right)\right\} = \frac {12}{s^2 + 4} converges to s> 0.

g. L \left\{-5\cos\left(2t + 1\right) \right\} = -5L\left\{\cos\left(2t + 1 \right)\right\} = -\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4} converges to s> 0.

h. L\left\{\sin \left(t\right)\cos \left(t\right)\right\} = L\left\{\sin\left(2t\right)\frac{1}{2}\right\} =\frac{1}{2}\cdot \frac{2}{s^2+4} = \frac {1} {s ^ 2 + 4} converges to s> 0.

7 0
4 years ago
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