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Fynjy0 [20]
2 years ago
14

If a line passes through (2, 4) and (5,-4), what is the slope?​

Mathematics
1 answer:
Mila [183]2 years ago
6 0

Answer:

So the slope is -8/3

Step-by-step explanation:

to find the slope you have to use m = y2-y1/x2-x1

so lets plug in our numbers

m = - 4- 4/5-2

 = -8/3

So the slope is -8/3

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PLEASE HELP ASAP
Ksenya-84 [330]
1. The area of the photograph is:
 
 A=LxW
 
 A is the area of the photograph (A=54 in²).
 L is the lenght of the photograph (L=12-4x).
 W is the widht of the photograph (W=12-2x)
 
 2. When you substitute these values into the formula A=LxW, you obtain:
 
 A=LxW
 54=(12-4x)(12-2x)
 
 3. When you apply the distributive property, you have:
 
 54=144-24x-48x+8x²
 8x²-72x+144-54=0
 
 4. Finally, you obtain a quadratic equation for the area of the photo:
 
 8x²-72x+90=0
 
 5. Therefore, the answer is:
 
 8x²-72x+90=0

6 0
2 years ago
93 divided by 3 using repeated subtraction
Naily [24]

93/3=31 Answer is 31

8 0
3 years ago
Read 2 more answers
The National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time requir
Paha777 [63]

Answer:

95​% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

Step-by-step explanation:

We are given that the National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time required to earn their bachelor’s degrees. The mean was 5.15 years and the standard deviation was 1.68 years respectively.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                              P.Q. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean time = 5.15 years

            \sigma = sample standard deviation = 1.68 years

            n = sample of college graduates = 4400

            \mu = population mean time

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics although we are given sample standard deviation because the sample size is very large so at large sample values t distribution also follows normal.</em>

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5%

                                               level of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ]

                                              = [ 5.15-1.96 \times {\frac{1.68}{\sqrt{4400} } } , 5.15+1.96 \times {\frac{1.68}{\sqrt{4400} } } ]

                                             = [5.10 , 5.20]

Therefore, 95​% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

8 0
3 years ago
What is the y-value of point A?
PSYCHO15rus [73]

Answer: 1

The full term is (6,1)

6 0
3 years ago
Read 2 more answers
17. El precio de los terrenos en Lima es proporcional al área e inversamente proporcional a su distancia con respecto al centro
grin007 [14]

Answer:

375000

Step-by-step explanation:

We have that in this case the following proportion would be fulfilled:

Price * Distance / area

Now, we have that for a distance of 45 km and an area of 900 m ^ 2 the price is 250,000, now for a distance of 40 km but with an area of 1,200 m ^ 2, how would the price be, we replace:

250000 * 45/900 = P * 40/1200

12500 * 1200/40 = P

P = 375000

Which means that for these conditions the price is 375000.

3 0
3 years ago
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