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3 years ago

Without actually solving the equation, explain why the equation √(x+1 + 2=0 has no solution.

Mathematics

1 answer:

mixas84 [53]3 years ago

7 0

Explanation:

The sum of something and 2 can only be zero when that something has a value of -2.

The range of the square root function is all non-negative numbers, so it cannot have a value of -2. Thus, the equation cannot have a solution.

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A number, y, is equal to the difference of a larger number and 3. The same number is one-third of the sum of the larger number a

rosijanka [135]

Answer:

Step-by-step explanation:

It's 21 lol

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3 years ago

A company has two types of machines, type R and type S. Operating at a constant rate, a machine of type R does a certain job in

kozerog [31]

Answer: C. 6

Step-by-step explanation:

Given : Time taken by Machine R to do the job = 36 hours

Time taken by Machine S to do the job = 18 hours

Let x be the number of each type of machine to do the job.

Then , according to the question the required equation will be :-

$\dfrac{x}{36}+\dfrac{x}{18}=\dfrac{1}{2}\\\\\Rightarrow\ x(\dfrac{1}{36}+\dfrac{1}{18})=\dfrac{1}{2}\\\\\Rightarrow\ \dfrac{x}{12}=\dfrac{1}{2}\\\\\Rightarrow\ x=\dfrac{12}{2}=6$

Hence, the number of machines of type R were used =6

8 0

3 years ago

Which of these numbers 3,4,18,111,123,340,345,456,555 are multiples of 33 but not 9?

LUCKY_DIMON [66]

Answer:

4 and 132

Step-by-step explanation:

4 x 33 = 132

the numbers 4 and 132 have nothing to do with 9, no matter what way you look at them

i hope this helps :)

4 0

3 years ago

Arianna is working two summer jobs, making $6 per hour walking dogs and making $10 per hour tutoring. In a given week, she can w

Mice21 [21]

Step-by-step explanation:

x = number hours dog walking

y = number hours tutoring

x + y <= 11

6x + 10y >= 80

the solution is the common area below the first line and above the second line.

the first line is above the second line (due to the y-intercept of 11 vs. 8) until the crossing point.

for the crossing point we use the regular equations :

from the first we get

x = 11 - y

using this in the second

6×(11 - y) + 10y = 80

66 - 6y + 10y = 80

4y = 14

y = 14/4 = 7/2 = 3.5

x = 11 - y = 11 - 3.5 = 7.5

so, she has to do at least 3.5 hours tutoring (and then 7.5 hours dog walking) for the minimum of $80 earning, all the way up to the maximum of 11 hours tutoring (and 0 dog walking) for $110 earning.

8 0

2 years ago

Find a polynomial P(x) with real coefficients having a degree 4, leading coefficient 4, and zeros 3-i and 4i.

Alisiya [41]

now, this polynomial has roots of 3-i and 4i, namely 3 - i and 0 + 4i.

let's bear in mind that a complex root never comes all by her lonesome, her sibling is always with her, the conjugate, so if 3 - i is there, 3 + i is also coming along, likewise if 0 + 4i is there, her sibling 0 - 4i is also there.

$\bf \begin{cases} x=3-i\implies &x-3+i=0\\ x=3+i\implies &x-3-i=0\\ x=4i\implies &x-4i=0\\ x=-4i\implies &x+4i=0 \end{cases}\\\\[-0.35em] ~\dotfill\\\\ (x-3+i)(x-3-i)(x-4i)(x+4i)=\stackrel{y}{0} \\[2em] \underset{\textit{difference of squares}}{[(x-3)+i][(x-3)-i]}\underset{\textit{difference of squares}}{[x-4i][x+4i]}=0$

$\bf [(x-3)^2-i^2][x^2-(4i)^2]=y\implies [(x-3)^2-(-1)][x^2-(4^2i^2)]=0 \\[2em] [(x-3)^2-(-1)][x^2-(16(-1))]=0\implies [(x-3)^2+1][x^2+16]=0 \\[2em] [(x^2-6x+9)+1][x^2+16]=y\implies (x^2-6x+10)(x^2+16)=0 \\\\\\ x^4-6x^3+10x^2+16x^2-96x+160=0 \\\\\\ x^4-6x^3+26x^2-96x+160=0 \\\\\\ \stackrel{\textit{multiplying both sides by 4}}{4(x^4-6x^3+26x^2-96x+160)=4(0)} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill 4x^4-24x^3+104x^2-384x+640=y~\hfill$

3 0

3 years ago