Answer:
15.3feet
Step-by-step explanation:
Given the scale model of a train as;
2cm = 3feet
We are to find the height of real train of height 10.2cm, we can write;
10.2cm = x
Divide both expressions
2/10.2 = 3/x
2x = 3×10.2
2x = 30.6
x= 15.3
Hence the height if the real train is 15.3feet
Answer:
Step-by-step explanation:
As the answer can be more simplified, divide both numerator and denominator by 5.
It can consist of translations (slides), reflections (flips), and rotations (turns).
I would say a reflection, then slide right, then slide down.
F(x) = 2^x; h(x) = x^3 + x + 8
Table
x f(x) = 2^x h(x) = x^3 + x + 8
0 2^0 = 1 0 + 0 + 8 = 8
1 2^1 = 2 1^3 + 1 + 8 = 10
2 2^2 = 4 2^3 + 2 + 8 = 8 + 2 + 8 = 18
3 2^3 = 8 3^3 + 3 + 8 = 27 + 3 + 8 = 38
4 2^2 = 16 4^3 + 4 + 8 = 76
10 2^10 = 1024 10^3 +10 + 8 = 1018
9 2^9 = 512 9^3 + 9 + 8 = 729 + 9 + 8 = 746
Answer: an approximate value of 10
