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alekssr [168]
3 years ago
9

Quadratic equations and complex numbers PPEASE ANSWER ASAP

Mathematics
2 answers:
mariarad [96]3 years ago
5 0

When you solve the following equation, solving for the quadratic formula.

The answer is; x=4

Next time pay attention in class.

cestrela7 [59]3 years ago
5 0

<u>Answer:</u>

12. x=-3\frac{1}{2}, x = 6

15. 4

<u>Step-by-step explanation:</u>

12. 2x^2-5x=42

To solve this quadratic equation, we will put all the variables and constants on one side of the equation and factorize it.

2x^2-5x-42=0

2x^2-12x+7x-42=0

2x(x-6)+7(x-6)=0

(2x+7)(x-6)=0

x=-\frac{7}{2}, x = 6

x=-3\frac{1}{2}, x = 6

Therefore, the solutions to the given expression are 3(1/2) and 6.


15. 3x=8+\sqrt{3x+4}

3x-8=\sqrt{3x+4}

Squaring both the sides to get:

(3x-8)^2=(3x+4)^2

9x^2-48x+64=3x+4

9x^2-51x+60=0

3(3x^2-17x+20)=0

3x^2-17x+20=0

3x^2-12x-5x+20=0

3x(x-4)-5(x-4)=0

x=\frac{3}{5} (ignore), x=4

Therefore, the solution to the given expression is 4.

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Answer:

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Step-by-step explanation:

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3 years ago
What two numbers multiply to 10 and add to -29 ?
Degger [83]
Xy=10
x+y=29

subtract x from both sides for second equation

y=-x-29
subsitute in second equaiton
x(-x-29)=10
-x^2-29x=10
add x^2+29x to both sides
x^2+29x+10=0
quadratic formula
if you have
ax^2+bx+c=0,
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

so
x^2+29x+10=0
a=1
b=29
c=10
x=\frac{-29+/- \sqrt{(-29)^{2}-4(1)(10)} }{2(1)}
x= \frac{-29+/- \sqrt{841-40} }{2}
x= \frac{-29+/- \sqrt{801} }{2}
x= \frac{-29+/- 3\sqrt{89} }{2}

x= \frac{-29- 3\sqrt{89} }{2} or \frac{-29+ 3\sqrt{89} }{2}
those are the 2 numbers
aprox=-28.65 and -0.349


5 0
3 years ago
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