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alekssr [168]
3 years ago
9

Quadratic equations and complex numbers PPEASE ANSWER ASAP

Mathematics
2 answers:
mariarad [96]3 years ago
5 0

When you solve the following equation, solving for the quadratic formula.

The answer is; x=4

Next time pay attention in class.

cestrela7 [59]3 years ago
5 0

<u>Answer:</u>

12. x=-3\frac{1}{2}, x = 6

15. 4

<u>Step-by-step explanation:</u>

12. 2x^2-5x=42

To solve this quadratic equation, we will put all the variables and constants on one side of the equation and factorize it.

2x^2-5x-42=0

2x^2-12x+7x-42=0

2x(x-6)+7(x-6)=0

(2x+7)(x-6)=0

x=-\frac{7}{2}, x = 6

x=-3\frac{1}{2}, x = 6

Therefore, the solutions to the given expression are 3(1/2) and 6.


15. 3x=8+\sqrt{3x+4}

3x-8=\sqrt{3x+4}

Squaring both the sides to get:

(3x-8)^2=(3x+4)^2

9x^2-48x+64=3x+4

9x^2-51x+60=0

3(3x^2-17x+20)=0

3x^2-17x+20=0

3x^2-12x-5x+20=0

3x(x-4)-5(x-4)=0

x=\frac{3}{5} (ignore), x=4

Therefore, the solution to the given expression is 4.

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We can see that revolving the region formed by intersecting 3 lines, we will get 2 cones that are connected their bases.
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1) small cone has r=5, and h=5
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3 years ago
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Answer: 30%

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Step-by-step explanation:

A Perfect-Square Trinomial is given by the form:

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The discriminant in the quadratic formula is:

\Delta=b^2-4ac \\ \\ \\ Here: \\ \\ a= \alpha^2 \\ \\ b=2\alpha \beta \\ \\ c=\beta^2 \\ \\ \\ So: \\ \\ \Delta=(2\alpha \beta )^2-4(\alpha^2)(\beta^2) \\ \\ \Delta=4\alpha^2 \beta^2-4\alpha^2 \beta^2=0

So in order to get a perfect square,<em> the discriminant must be zero.</em>

<em></em>

<h2>Learn more:</h2>

Discriminant: brainly.com/question/1537997

#LearnWithBrainly

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