Answer:
h = 
Step-by-step explanation:
Formula for the area of a trapezoid is,
Area (A) = 
Here b and c are the bases and 'h' is the height of the trapezoid.
2A = ![2[\frac{1}{2}(b+c)h]](https://tex.z-dn.net/?f=2%5B%5Cfrac%7B1%7D%7B2%7D%28b%2Bc%29h%5D)
2A = (b + c)h
Therefore, formula for the height of the trapezoid will be,
h =
Given J(1, 1), K(3, 1), L(3, -4), and M(1, -4) and that J'(-1, 5), K'(1, 5), L'(1, 0), and M'(-1, 0). What is the rule that tran
anastassius [24]
(x; y) -> (x - 2; y + 4)
J(1; 1) ⇒ J'(1 - 2; 1 + 4) = (-1; 5)
K(3; 1) ⇒ K'(3 - 2; 1 + 4) = (1; 5)
L(3;-4) ⇒ L'(3 - 2; -4 + 4) = (1; 0)
M(1;-4) ⇒ M'(1 - 2;-4 + 4) = (-1; 0)
Answer:
f(- 2) = 1
Step-by-step explanation:
f(- 2) means what is the value of f(x) when x = - 2
From the table we can see that when x = - 2 f(x) = 1
Hence
f(- 2) = 1
The answer is true. Hope this helps. Mark brainest
Answer:
All you need to do is to calculate the perimeter of the circle since you already had the diameter
Base on the picture, the perimeter should be:
C = d * π = 64 * 3.14 = 200.96 (m)
