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Delicious77 [7]
3 years ago
7

The width of a rectangle is equal to m cm, but its length is five times greater than the width. Find the area of the rectangle

Mathematics
1 answer:
netineya [11]3 years ago
5 0

Answer:

Area of rectangle is, 5m^2 square cm.

Step-by-step explanation:

Given: The width of a rectangle (w) = m cm

As per the condition; length(l) is five times greater than the width i.e,

l = 5w cm

Now, to find the area of a rectangle(A) multiply its length(l) by its width(w) i.e,

A = l\times w square unit .

Substitute the value of l and w in above formula;

A = l \times w = (5w) \times w = 5w^2 = 5(m)^2 = 5m^2 square cm.

Therefore, the area of rectangle is; 5m^2 square cm.

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Answer:6.7

Step-by-step explanation:

5t-17.2=16.3

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4 0
3 years ago
A train leaves thorn junction at 1:25 p.m. and arrives in niles at 3:05 p.m. the train makes two stops along the route for a tot
KonstantinChe [14]

The time taken by the first and the second train is 1 hour 40 minutes and 1 hour 25 minutes. Then the time when the second train at Niles junction is 5:55 p.m.

<h3>What is speed?</h3>

The distance covered by the particle or the body in an hour is called speed. It is a scalar quantity. It is the ratio of distance to time.

We know that the speed formula

\rm Speed = \dfrac{Distance}{Time}

A train leaves Thorn junction at 1:25 p.m. and arrives in Niles at 3:05 p.m. the train makes two stops along the route for a total of 15 minutes.

A second train leaves Thorn junction at 4:30 p.m. and heads to Niles.

This train does not make any stops.

Let the speed of both trains be equal.

Then the time taken by the first train will be

t₁ = 3:05 p.m. - 1:25 p.m.

t₁ = 1 hour 40 minutes

Then the time taken by the second train will be

t₂ = 1:40 - 00:15

t₂ = 1:25 = 1 hour 25 minutes

The time when the second train is at Niles junction will be

→ 4:30 p.m. + 1:25

→ 5:55 p.m.

More about the speed link is given below.

brainly.com/question/7359669

#SPJ1

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Step-by-step explanation:

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