Answer:
- large: 40 lbs
- small: 20 lbs
Step-by-step explanation:
A system of equations can be written for the weights of the boxes based on the relationships given in the problem statement. One equation will be for the total weight of 1 large and 1 small box; the other will be for the total weight of 70 large and 60 small boxes.
Let L and S represent the weights of Large and Small boxes, respectively. The system of equations is ...
L + S = 60 . . . . . . combined weight is 60 lbs
70L +60S = 4000 . . . . weight of boxes in the truck
__
We can solve this by substituting for s in the second equation.
70L +60(60 -L) = 4000
10L = 400 . . . . . . . . . subtract 3600, simplify
L = 40
S = 60 -L = 20
A large box weighs 40 pounds; a small box weighs 20 pounds.
A squared plus b squared = c squared will help
Answer:
The answer is a: Number of items in several classes.
Step-by-step explanation:
Frequency distributions are tables that represent the number of times a specific data, number object etc appears in a sample. So for example if we have this data
2,2,4,4,6,6,6,8,8,10
The frequency distributions is
Number frequency
2 2
4 2
6 3
8 2
10 1
The other options are identical (c and are the same as percentages can be expressed as fractions. Relative percentages or fractions are tables that express the weight that each category has in the entire data. An example for our data would be: (10 are the total number of obs)
Number Fraction/%
2 2/10 or 20%
4 2/10 or 20%
6 3/10 or 30%
8 2/10 or 20%
10 1/10 or 10%
Answer:
24.08
Step-by-step explanation:
We use the Pythagorean theorem and we get (16)^2 + (18)^2 = (x)^2
256 + 324 = x^2
x^2 = 580
x is about 24.08.
