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3 years ago

What is the equation of the line using the information below? m= 10 and b=-3 Equation=

Mathematics

2 answers:

Elena-2011 [213]3 years ago

8 0

The answer is Y=10x-3 if that’s the type of equation you wanted.

Nostrana [21]3 years ago

6 0

Answer:

y= 10x-3

Step-by-step explanation:

If you are using the y=mx+b model, the above answer is correct. M represents the slope and B represents the y-intercept.

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PLEASE HELP!!! WHOEVER GETS THE ANSWER RIGHT GETS BRAINLIEST!!!

masha68 [24]

There is 4 X so you use 360- (11+1) which is 348 and now divide by 4 which is now 87

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2 years ago

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Classify the following triangle check all that apply

Mademuasel [1]

Answer:

Right, Acute, Scalene.

Step-by-step explanation:

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3 years ago

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Use the midpoint formula to find the midpoint between H(3, 9) and J(9, -2).

TiliK225 [7]

Hello!

The midpoint formula is basically an average of x and y.

It is also written as: $(\frac{x_{1}+x_{2}} {2},\frac{y_{1}+ y_{2}} {2})$ .

With the formula above, we can substitute the given points into the equation, and simplify.

$(\frac{3 +9}{2}, \frac{9+(-2)}{2}) = (\frac{12}{2}, \frac{7}{2}) = (6, 3.5)$

Therefore, the midpoint between points H and J is choice D, (6, 3.5).

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3 years ago

A rope is 66 feet long. It is cut into two pieces such that one piece is half the length of the other. What is the length of the

Masja [62]

22 feet is the answer

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3 years ago

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A bag contains 3 pink gumballs, 4 red gumballs, and 2 green gumballs. Find the probability that a red gumball is drawn if there

fgiga [73]

Answer:

0.99

Step-by-step explanation:

Given,

Pink gumballs = 3,

Red gumballs = 4,

Green gumballs = 2,

So, total gumballs = 3 + 4 + 2 = 9,

Thus, total ways of selecting 5 gumball = $^9C_5$

$=\frac{9!}{5!4!}$

$=\frac{9\times 8\times 7\times 6}{24}$

$=9\times 2\times 7$

$=126$

Also, the total ways of selecting no red gumballs = $^4C_0\times ^5C_5$

= 1 × 1

= 1

So, the probability of no red gumballs in 5 drawn

$=\frac{1}{126}$

Hence, the probability that a red gumball is drawn if there are 5 drawings

= 1 - probability of no red gumballs

$=1-\frac{1}{126}$

$=\frac{125}{126}$

≈ 0.99

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3 years ago

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