15)

1. The alphabet which can assume<br> different values is called: *

Sedaia [141]

Answer:

variable

Step-by-step explanation:

8 0

3 years ago

Claire mowed 7 lawns last week. She mowed each lawn in 7/18 hour. She mowed the same lawns this week in 5/18 hour. How many time

Wittaler [7]

I think it’s 2 hours

7 0

3 years ago

Quizzzz !! Plzzzz help

Tomtit [17]

QUESTION 1

a) The zeros of the function are the x-values at which the graph touches the x-axis.

From the graph, the zeros are;

$x=0,x=-4$

b) The axis of symmetry is the vertical line that goes through the vertex of the parabola.

$x=-2$

c) The maximum value is the y-value of the vertex.

Max: y=4

d) The vertex is the maximum point on the graph.

Vertex: (-2,4).

QUESTION 2

a) The graph touches the x-axis at only one point.

From the graph, the zero is $x=-2$

b) The axis of symmetry is the vertical line that goes through the vertex of the parabola.

$x=-2$

c) The minimum value is the y-value of the vertex.

Min: y=0

d) The vertex is the minimum point on the graph.

Vertex: (-2,0).

QUESTION 3

a) The graph touches the x-axis at two points.

From the graph, the zeros are $x=-3,x=3$

b) The axis of symmetry is the vertical line that goes through the vertex of the parabola.

$x=0$

c) The minimum value is the y-value of the vertex.

Min: y=-9

d) The vertex is the minimum point on the graph.

Vertex: (0,-9).

QUESTION 4

a) The zeros of the function are the x-values at which the graph touches the x-axis.

From the graph, the zeros are;

$x=-3,x=-5$

b) The axis of symmetry is the vertical line that goes through the vertex of the parabola.

$x=-4$

c) The maximum value is the y-value of the vertex.

Max: y=1

d) The vertex is the maximum point on the graph.

Vertex: (-4,1).

QUESTION 5

a) The graph touches the x-axis at two points.

From the graph, the zeros are $x=3,x=7$

b) The axis of symmetry is the vertical line that goes through the vertex of the parabola.

$x=5$

c) The minimum value is the y-value of the vertex.

Min: y=-4

d) The vertex is the minimum point on the graph.

Vertex: (5,-4).

QUESTION 6

a) The graph does not touch the x-axis.

The function has no real zeros.

b) The axis of symmetry is the vertical line that goes through the vertex of the parabola.

$x=2$

c) The minimum value is the y-value of the vertex.

Min: y=5

d) The vertex is the minimum point on the graph.

Vertex: (2,5).

QUESTION 7

a) The graph touches the x-axis two points.

The function has zeros at x=1 and x=5

b) The axis of symmetry is the vertical line that goes through the vertex of the parabola.

$x=3$

c) The minimum value is the y-value of the vertex.

Min: y=-4

d) The vertex is the minimum point on the graph.

Vertex: (3,-4).

QUESTION 8

a) The zeros of the function are the x-values at which the graph touches the x-axis.

From the graph, the zeros are;

$x=0,x=-2$

b) The axis of symmetry is the vertical line that goes through the vertex of the parabola.

$x=-1$

c) The maximum value is the y-value of the vertex.

Max: y=1

d) The vertex is the maximum point on the graph.

Vertex: (-1,1).

QUESTION 9

a) The graph touches the x-axis at only one point.

From the graph, the zero is $x=5$

b) The axis of symmetry is the vertical line that goes through the vertex of the parabola.

$x=5$

c) The minimum value is the y-value of the vertex.

Min: y=0

d) The vertex is the minimum point on the graph.

Vertex: (5,0).

5 0

4 years ago

Ahmad lost 50 dollars from his pocket.<br><br>Write a signed number to represent this change.

IRINA_888 [86]

Answer:

-50

Step-by-step explanation:

it could be X-50=?

8 0

3 years ago

Which has the greater surface area? A 6-centimeter cube or a rectangular prism with a 3 centimeter square base and a height of 1

bazaltina [42]

Answer:

The prism

Step-by-step explanation:

The surface area of a cube is:

$A=6L^2$

where

L is the length of the side

For the cube in this problem,

L = 6 cm

So the surface area of the cube is

$A=6\cdot 6^2 = 36 cm^2$

The surface area of a rectangular prism with squared base is:

$A=2L^2+4Lh$

where

L is the length of the base

h is the height of the prism

For the prism in this problem,

L = 3 cm

h = 12 cm

Therefore,

$A=2\cdot 3^2 + 4(3)(12)=162 cm^2$

So, the prism has a greater surface area.

3 0

3 years ago