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vova2212 [387]
3 years ago
11

A rectangle has an area of 42 cm²; the length is 7 cm. Find its width.

Mathematics
1 answer:
liubo4ka [24]3 years ago
7 0
You would have 6cm as the width because length times width = area
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Write an equation of the line perpendicular to the given line that contains P.
lara31 [8.8K]

Answer:

Step-by-step explanation:

perp. -5

y + 7 = -5(x - 4)

y + 7 = -5x + 20

y = -5x + 13

7 0
3 years ago
Your $440 gets 5.8% interest compounded annually for 8 years. What will your
ladessa [460]

Answer:

492.52

Step-by-step explanation:

The formula is P(t) = P(0) x (1+r/n)^nt so...

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P(t) = 492.52

3 0
3 years ago
The area of a rectangle is represented by the function A = n^3 - 6n^2 - 8n + 48.
aliya0001 [1]

Answer:

P = 2(n - 6) + 2(n^2 - 8)

Step-by-step explanation:

Remembering that Area = Length times Width, we factor the given function

A = n^3 - 6n^2 - 8n + 48 in the expectation that the resulting factors represent the length and width respectively:

A = n^3 - 6n^2 - 8n + 48 factors as follows:

A = n^2(n - 6) - 8(n - 6), or A = (n - 6)(n^2 - 8)

We can label '(n - 6)' "width" and '(n^2 - 8'

length.

Then the perimeter, P, of the rectangle is P = 2(length) + 2(width). which works out here to:

P = 2(n - 6) + 2(n^2 - 8)

5 0
2 years ago
Need help on this, need help now D:
baherus [9]

Answer:

\sqrt{34}

Step-by-step explanation:

Calculate the distance using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = A(- 2, 5) and (x₂, y₂ ) = B(3, 8)

d = \sqrt{(3+2)^2+(8-5)^2}

   = \sqrt{5^2+3^2}

   = \sqrt{25+9}

   = \sqrt{34}

5 0
3 years ago
Question Help
drek231 [11]
He drove 140 miles you take 245 divide by 7 then times by 4
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3 years ago
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