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nirvana33 [79]
3 years ago
5

Nathan wants to draw a triangle. He knows that two of the side lengths are 5 inches and 7 inches. What is a possible length for

the third side?
Mathematics
2 answers:
Talja [164]3 years ago
6 0

Answer:

the third side would be 5 inches.

Step-by-step explanation:

olga55 [171]3 years ago
3 0

Answer:

7 inches

Step-by-step explanation:

Hope this Helps!

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Simplify. Write your answer using whole numbers and variables.
Andre45 [30]

Answer:

q + 7

Step-by-step explanation:

(q² + 4q − 21) / (q − 3)

Factor the numerator:

(q + 7) (q − 3) / (q − 3)

Divide:

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3 years ago
I need help with this question
egoroff_w [7]

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C. No, because there is an input value that has two different output values.

Step-by-step explanation:

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3 0
3 years ago
A tire manufacturer warranties its tires to last at least 20,000 miles orâ "you get a new set ofâ tires." In itsâ experience, a
Y_Kistochka [10]

Answer:

Probability that a set of tires wears out before 20,000 miles is 0.1151.

Step-by-step explanation:

We are given that a tire manufacturer warranties its tires to last at least 20,000 miles or "you get a new set of tires." In its past experience, a set of these tires last on average 26,000 miles with S.D. 5,000 miles. Assume that the wear is normally distributed.

<em>Let X = wearing of tires</em>

So, X ~ N(\mu=26,000,\sigma^{2}=5,000^{2})

Now, the z score probability distribution is given by;

         Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = average lasting of tires = 26,000 miles

            \sigma = standard deviation = 5,000 miles

So, probability that a set of tires wears out before 20,000 miles is given by = P(X < 20,000 miles)

    P(X < 20,000) = P( \frac{X-\mu}{\sigma} < \frac{20,000-26,000}{5,000} ) = P(Z < -1.2) = 1 - P(Z \leq 1.2)

                                                                    = 1 - 0.88493 = 0.1151

Therefore, probability that a set of tires wears out before 20,000 miles is 0.1151.

4 0
3 years ago
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