Question

Y= -3(x-3)^2+4 identify the axis of symmetry.

Answer 1

ANSWER

x=3

EXPLANATION

The given function is

$y= -3(x-3)^2+4$

This function is of the form.

$y= a(x-h)^2+k$

This is called the vertex form.

The axis of symmetry is given by

$x = h$

By comparing to

$y= -3(x-3)^2+4$

a=-3, h=3 and k=4

Hence the axis of symmetry is x=3

Answer 2

Answer:

The equation of the axis of symmetry is x = 3

Step-by-step explanation:

Perform the indicated mult., obtaining:

y = 3(x² - 6x + 9) + 4.

Mult. each term inside parentheses by 3, we get:

y = 3x² - 18x + 27 + 4, or

y + 3x² - 18x + 31

Here the coefficients are a = 3, b = -18 and c = 31.

The axis of symmetry is x = -b / (2a), which here is:

      -(-18)

x = ----------- = 18/6 = 3

       2(3)

The equation of the axis of symmetry is x = 3