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sammy [17]
3 years ago
10

Câu 1: Giả sử, có số liệu tối đa hai mặt hàng chuối và táo mà Việt Nam và Trung Quốc có thể sản xuất được trong điều kiện sử dụn

g hết tài nguyên và kỹ thuật tốt nhất:
NSLĐ (ngàn tấn/năm) Thái Lan Nhật Bản
Táo 160 400
Chuối 800 600
a) Hãy phân tích cơ sở, mô hình và khung tỷ lệ trao đổi?
b) Xác định chi phí cơ hội về mỗi sản phẩm tại mỗi quốc gia?
c) Ở TLTĐ nào thì lợi ích MDQT giữa 2 QG bằng nhau?
d) Giả sử, điểm sản xuất tự cung tự cấp của Việt Nam là A (400C ; 80T) và Trung Quốc là A’(300C ; 200T). Xác định lợi ích của 2 quốc gia bằng biểu đồ?
Mathematics
1 answer:
satela [25.4K]3 years ago
4 0

Answer:

cat cat cat cat cat cat cat cat cat cat cat cat cat

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50 points please help
SashulF [63]

Answer:

What are in the boxes?

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
(5) Find the Laplace transform of the following time functions: (a) f(t) = 20.5 + 10t + t 2 + δ(t), where δ(t) is the unit impul
Aloiza [94]

Answer

(a) F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}

(b) F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}

Step-by-step explanation:

(a) f(t) = 20.5 + 10t + t^2 + δ(t)

where δ(t) = unit impulse function

The Laplace transform of function f(t) is given as:

F(s) = \int\limits^a_0 f(s)e^{-st} \, dt

where a = ∞

=>  F(s) = \int\limits^a_0 {(20.5 + 10t + t^2 + d(t))e^{-st} \, dt

where d(t) = δ(t)

=> F(s) = \int\limits^a_0 {(20.5e^{-st} + 10te^{-st} + t^2e^{-st} + d(t)e^{-st}) \, dt

Integrating, we have:

=> F(s) = (20.5\frac{e^{-st}}{s} - 10\frac{(t + 1)e^{-st}}{s^2} - \frac{(st(st + 2) + 2)e^{-st}}{s^3}  )\left \{ {{a} \atop {0}} \right.

Inputting the boundary conditions t = a = ∞, t = 0:

F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}

(b) f(t) = e^{-t} + 4e^{-4t} + te^{-3t}

The Laplace transform of function f(t) is given as:

F(s) = \int\limits^a_0 (e^{-t} + 4e^{-4t} + te^{-3t} )e^{-st} \, dt

F(s) = \int\limits^a_0 (e^{-t}e^{-st} + 4e^{-4t}e^{-st} + te^{-3t}e^{-st} ) \, dt

F(s) = \int\limits^a_0 (e^{-t(1 + s)} + 4e^{-t(4 + s)} + te^{-t(3 + s)} ) \, dt

Integrating, we have:

F(s) = [\frac{-e^{-(s + 1)t}} {s + 1} - \frac{4e^{-(s + 4)}}{s + 4} - \frac{(3(s + 1)t + 1)e^{-3(s + 1)t})}{9(s + 1)^2}] \left \{ {{a} \atop {0}} \right.

Inputting the boundary condition, t = a = ∞, t = 0:

F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}

3 0
3 years ago
What is every number in pie? please put all numbers!
Mila [183]

Answer: The number pi is an irrational number

Step-by-step explanation:

Pi is irrational because it will never end and at the same time doesnt have a pattern in which the numbers repeat. Here are some of the numbers in pi 3.14159265359

8 0
4 years ago
Add a restaurant after every 12 visit you receive a free beverage after every 15 where is it you receive a free dessert which vi
elena55 [62]
You will receive a free beverage and free desert on your 60th visit.

Beverage- 1, 2, 3, 4, 5, 6
Visits- 12, 24, 36 ,48 ,60


Desert- 1, 2, 3 ,4
Visits- 15, 30, 45, 60

Notice how for beverages at 60 visits you get your 6th drink for free, and for deserts, at you 60 visits you receive your 4 free desert.

So, since both numbers have the same number (60) of visits which is their common multiple between the 2, you answer is 60.
8 0
4 years ago
Read 2 more answers
PLEASE HELP NEED THIS DONE ASAP
kenny6666 [7]

Answer:

The area of rhombus PQRS is 120 m.

Step-by-step explanation:

Consider the rhombus PQRS.

All the sides of a rhombus are equal.

Hence, PQ = QR = RS = SP = 13 m

The diagonals PR and QS bisect each other.

Let the point at of intersection of the two diagonals be denoted by <em>X</em>.

Consider the triangle QXR.

QR = 13 m

XR = 12 m

The triangle QXR is a right angled triangle.

Using the Pythagorean theorem compute the length of QX as follows:

QR² = XR² + QX²

QX² = QR² - XR²

       = 13² - 12²

       = 25

 QX = √25

       = 5 m

The measure of the two diagonals are:

PR = 2 × XR = 2 × 12 = 24 m

QS = 2 × QX = 2 × 5 = 10 m

The area of a rhombus is:

\text{Area}=\frac{1}{2}\times d_{1}\times d_{2}

Compute the area of rhombus PQRS as follows:

\text{Area}=\frac{1}{2}\times PR\times QS

        =\frac{1}{2}\times 24\times 10\\\\=120

Thus, the area of rhombus PQRS is 120 m.

5 0
3 years ago
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