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3 years ago

PLEASE HELP GEOMETRY !!!!!

Mathematics

1 answer:

statuscvo [17]3 years ago

8 0

Answer:

x = 11.5

Step-by-step explanation:

$\sin \: 35 \degree = \frac{x}{20} \\ \\ x = 20 \sin \: 35 \degree \\ \\ x = 11.471528727 \\ \\ x = 11.5$

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Two lines intersect and two of the vertical angles measure 37°. What is the measure of the other two vertical angles?

Shtirlitz [24]

Answer:

286 degrees and 143 degrees

Step-by-step explanation:

When line intersect the two vertical angle adds up to 180 degrees

To find the other vertical angle:

180 -37=143 degrees

So for two vertical angles

we take (180*2)-(37*2)=286 degrees

8 0

3 years ago

According to the U.S. Census Bureau, 42% of men who worked at home were college graduates. In a sample of 480 women who worked a

Likurg_2 [28]

Answer:

1) $0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315$

The point estimate for the proportion of college graduates among women who work at home is 0.327

2) $0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315$

$0.327 + 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.339$

The 80% confidence interval is given by (0.315; 0.339)

Step-by-step explanation:

For this case we have the following info given:

$X = 157$ represent the women who worked at home who were college graduates

$n = 480$ the sample size selected

Part 1

In order to find the proportion of college graduates among women who work at home and we can use the following formula:

$\hat p=\frac{X}{n} = \frac{157}{480}= 0.327$

The point estimate for the proportion of college graduates among women who work at home is 0.327

Part 2

Construct an 80% confidence interval for the proportion of women who work at home who are college graduates. Round the answer to three decimal places. An 80% confidence interval for the proportion of women who work at home Is < p <

The confidence interval for the true proportion would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 80% confidence interval the value for the significance is $\alpha=1-0.8=0.2$ and $\alpha/2=0.1$ , the critical value would be given by:

$z_{\alpha/2}=0.539$

And replacing we goot:

$0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315$

$0.327 + 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.339$

The 80% confidence interval is given by (0.315; 0.339)

6 0

3 years ago

How long will it take to administer 1000 cc at a drop factor of 15 drop/ml and a drip rate of 50 drop/min

gayaneshka [121]

First, we are going to determine the number of drops that needs to be administered by dividing the total volume by the volume per drop. Since, 1 cc (cm³) is equal to 1 mL then, 1000 cc is equal to 1000 mL.

n = (1000 mL)(15 drop/1 mL) = 15000 drops

Then, divide the number of drops by the number of drops per minute.

N = (15000 drops)/ (50 drop/min) = 300 mins

Answer: 300 mins or 5 hours

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Answer:

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Step-by-step expla

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