What is the solution of this system of linear equations? 3y=3/2x+6 1/2y-1/4x=3.

Mathematics

1 answer:

tensa zangetsu [6.8K]3 years ago

5 0

Answer:

No solution

Step-by-step explanation:

Please, separate equations with a comma, or the word "and," or a semicolon.

Next, determine the LCD and multiply both equations by it, so as to elimiinate the fractional coefficients.

3y=3/2x+6 1/2y-1/4x=3

should be written as the system

3y=(3/2)x+6 Use parentheses around the fraction for clarity

(1/2)y-(1/4)x=3 Same: use parentheses

The LCDs here are 2 (for the first equation) and 4 (for the second equation). Multiply the first equation by 2 to eliminate the fractions:

3y=(3/2)x+6 → 6y = 3x + 12, and

4[ (1/2)y-(1/4)x=3 ] → 2y - x = 12

Let's use the substitution method to solve this system. Solve the 2nd equation for x, obtaining x = 2y - 12. Substitute 2y - 12 for x in the 1st equation 6y = 3x + 12:

6y = 3(2y - 12) + 12, or

6y = 6y - 36 + 12

This reduces to 0 = -24, which is never true. Thus,

this system has NO solution.

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Dilation is when you stretch something by the same amount in two perpendicular directions. In other words, dilation changes size, not overall shape. Dilation factors greater than one makes the shape greater while dilation factors less than one makes the shape smaller. The scale factor in this problem is:

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