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Vlada [557]
3 years ago
5

Solve the system.

Mathematics
1 answer:
anyanavicka [17]3 years ago
3 0
X= -2
Y= -1
Z= 1
You may use solve this problem by substituting the values as well. If everything goes wrong , go for Cramer’s rule
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Which value of x makes the equation below true? 7 + x = 84 A. 12 B. 77 C. 83 D. 91
garri49 [273]

Answer:

B. 77

Step-by-step explanation:

7 + x = 84

Subtract 7 from both sides

x = 77

8 0
2 years ago
Find the slope<br> (19, -16) (-7, -15
wariber [46]

Answer:

Y-Intercept (-3,4) , (19,7). (−3,4) ( - 3 , 4 ) , (19,7) ( 19 , 7 ). Find the value of the slope.

Step-by-step explanation:

6 0
2 years ago
33. The perimeter of a room is 22m.lf<br> the length of the room is 6.5m,<br> what is its width?
vredina [299]

The formula for perimeter is 2(Length) + 2(width)

Fill in the known information:

22 = 2(6.5)+ 2(width)

Simplify:

22 = 13 + 2(width)

Subtract 13 from both sides:

9 = 2(width)

Divide both sides by 2:

Width = 4.5m

4 0
3 years ago
What is the domain of F(x) = In(x)?
jekas [21]

Answer as an inequality:  x > 0

Answer in interval notation:  (0, \infty)

Answer in words: Set of positive real numbers

All three represent the same idea, but in different forms.

======================================================

Explanation:

Any log is the inverse of an exponential equation. Consider a general base b such that f(x) = b^x. The inverse of this is f^{-1}(x) = \log_b(x)

For the exponential b^x, we cannot have b^x = 0. We can get closer to it, but we can't actually get there. The horizontal asymptote is y = 0.

Because of this, \log_b(x) has a vertical asymptote x = 0 (recall that x and y swap, so the asymptotes swap as well). This means we can get closer and closer to x = 0 from the positive side, but never reach x = 0 itself.

The domain of \log_b(x) is x > 0 which in interval notation would be (0, \infty). This is the interval from 0 to infinity, excluding both endpoints.

------------------------

The natural log function Ln(x) is a special type of log function where the base is b = e = 2.718 approximately.

So,

\log_e(x) = \text{Ln}(x)

allowing all of what was discussed in the previous section to apply to this Ln(x) function as well.

------------------------

In short, the domain is the set of positive real numbers. We can't have x be 0 or negative.

8 0
3 years ago
Please help with this question<br> Only real answers please.
Evgesh-ka [11]

minimum (-2,-2)

hope this will help

6 0
3 years ago
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