Ask question

Ask question

All categories

3 years ago

5

Solve the system.

1 answer:

anyanavicka [17]3 years ago

3 0

X= -2
Y= -1
Z= 1
You may use solve this problem by substituting the values as well. If everything goes wrong , go for Cramer’s rule

You might be interested in

How does the decimal point move when 0.45 is multiplied by 10 to the 4 power.

DochEvi [55]

Answer:

450,000.

Step-by-step explanation:

The decimal point moves to the right, because 10 to the power of 4 is 10,000.

6 0

3 years ago

Read 2 more answers

What is the solution to the system of equations shown in the graph?

Helen [10]

Answer:

B) (-2,1)

Step-by-step explanation:

The solution is where the two lines intersect, in this case at (-2,1)

Hope this helps! :)

7 0

3 years ago

Read 2 more answers

Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl

amm1812

Answer:

1. $P(s_1|I)=\frac{1}{11}$

2. $P(s_2|I)=\frac{8}{11}$

3. $P(s_3|I)=\frac{2}{11}$

Step-by-step explanation:

Given information:

$P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3$

$P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1$

(1)

We need to find the value of P(s₁|I).

$P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}$

$P(s_1|I)=\frac{0.015}{0.165}$

$P(s_1|I)=\frac{1}{11}$

Therefore the value of P(s₁|I) is $\frac{1}{11}$ .

(2)

We need to find the value of P(s₂|I).

$P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}$

$P(s_2|I)=\frac{0.12}{0.165}$

$P(s_2|I)=\frac{8}{11}$

Therefore the value of P(s₂|I) is $\frac{8}{11}$ .

(3)

We need to find the value of P(s₃|I).

$P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}$

$P(s_3|I)=\frac{0.03}{0.165}$

$P(s_3|I)=\frac{2}{11}$

Therefore the value of P(s₃|I) is $\frac{2}{11}$ .

4 0

3 years ago

28÷x=168<br>What is the value of "x"

coldgirl [10]

It is 1/6 or .16 I used Photomath

7 0

3 years ago

There are 20 juice cups and each juice cup holds 10 fluid ounces. the juice comes in 1 gallon bottles. how many 1 gallon bottles

Andru [333]

20 times 10=200 fluid ounces

128 fluid ounces per gallon
1 gallon is too little
2 gallons is to much
but you can't buy 1 and 72/100 of a bottle so just buy 2

2 bottles

6 0

3 years ago