Answer:
Step-by-step explanation:
We first need to define a couple of variables. Let s = the cost of 1 squash and z = the cost of 1 zucchini.
Now lets translate the words into algebra:
"The cost of 5 squash and 2 zucchini is $1.32" ===> 5s + 2z = 1.32
"Three squash and 1 zucchini cost $0.75" ===> 3s + z = 0.75
There are several ways to solve systems of equations. Let's use substitution. We can find what z equals in terms of s by manipulating the second equation:
3s + z = 0.75
-3s -3s
------------ -------------
z = -3s +0.75
Now lets substitute (-3s + 0.75) into the first equation for z, then solve for s:
5s + 2(-3s + 0.75) = 1.32
Can you handle it from here?
(Hint: Once you have solved for s, you can substitute that value back into either of the equations and solve for z.)
Answer:
It's fine. It is a function. The language can be very convoluted. Put simply a domain value cannot have 2 different range values.
Step-by-step explanation:
The confusing part I think, is probably the fact that -1 and 1 both have an answer of 5.
That's fine. Parabolas do that and they are functions. Two different xs can have the same value. The thing that eliminates functions is when the x value (the domain) has two different y values (the range values). Then you don't have a function.
To try and make it clearer if 1 pointed at both 3 and 5 you would not have a function.
Answer:
(x+3)(x+2)
Step-by-step explanation:
take x^2 and take it apart. so it should be (x+ ) (x+ ) then take 6 and make it so it's multipuls equal 5. ur answer should be (x+3)(x+2) or vice versa.
