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3 years ago

Mike swam 50 meters in 27.5 seconds. at that rate how long would it take mike to swim 400 meters

1 answer:

8 0

It would take 110 seconds or a minute and 40 seconds. 400 divided by 50 = 4...... 27.5 multiplied by 4 equals 110; therefore, the answer is mike would swim 400 meters in 110 seconds.

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Find the amount of the discount on a $140 bicycle that is on sale for 30% off A.$98.00 B.$32.00 C.$42.00 D.$4.20

Marrrta [24]

140 * 0.30 = 42

the discount would be C. $42.00

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3 years ago

Read 2 more answers

PLS HELP FIRST TO ANSWER GETS Brainlest

Nezavi [6.7K]

Answer:

It is 4

Step-by-step explanation:

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2 years ago

Rename the number 780000 = 78

AfilCa [17]

<span>We need to rename the given number which is 780 000 into 78 ________.
=> But before we rename it, we need to find the value of 78
=> Since this is a 6 digit whole number, we have ones, tens, hundreds, thousands, ten thousands, hundred thousands.
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3 years ago

What has she done wrong?

Strike441 [17]

Answer:

see explanation

Step-by-step explanation:

Her error is in squaring (2y)²

She has (2y)² = 2y²

when it should be 2y × 2y = 4y²

Then

(2y)² = 6² + 8²

4y² = 36 + 64

4y² = 100 ( divide both sides by 4 )

y² = 25 ( take square root of both sides )

y = $\sqrt{25}$ = 5

8 0

2 years ago

Find the length of the tangent segment AB to the circles centered at O and O' whose radii are a and b respectively when the circ

bixtya [17]

Answer:

$AB=2\sqrt{ab}$

Step-by-step explanation:

From figure,

$OA=a, \quad \quad O'B=b\\\Rightarrow OO'= (a+b) \quad \quad \text{and}\quad OD=(a-b)$

In triangle $OO'D$

$(OO')^2=(OD)^2+(O' D)^2$

$\Rightarrow (a+b)^2=(a-b)^2+(O' D)^2\\\Rightarrow a^2+b^2+2ab-a^2-b^2+2ab=(O' D)^2\\\Rightarrow 4ab=(O' D)^2\\\Rightarrow O'D=2\sqrt{ab} \\\Rightarrow O' D=2\sqrt{ab}=AB \quad \quad [\because O' DAB\;\; \text{is a rectangle.}]$

Hence, $AB=2\sqrt{ab}$

6 0

3 years ago