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cestrela7 [59]
3 years ago
6

Find the Coordinates of the midpoint of the segment whose endpoints are H(8,2) and K(6,10)

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
5 0
I hope this helps you

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How are the measures of angles, arcs and segments formed by secant lines that intersect within a circle related?
Drupady [299]

Answer:

The answers below ._.

Step-by-step explanation:

A secant is a line that intersects a circle in exactly two points. When a tangent and a secant, two secants, or two tangents intersect outside a circle then the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs.

6 0
3 years ago
Read 2 more answers
Find the volume of a regular hexahedron if one of the diagonals of its faces is 8 root 2 inches.
Naily [24]
The answer is 114sqrt{6} in³

A regular hexahedron is actually a cube. 

Diagonal of a cube D is a hypotenuse of a right triangle which other two legs are face diagonal (f) and length of a side (a):
D² = f² + a²

Face diagonal is a hypotenuse of a right triangle which sides are a and a:
f² = a² + a² =2a²

D² = f² + a²
f² = 2a²

D² = 2a² + a² = 3a²
D = √3a² = √3 * √a² = √3 * a = a√3

Volume of a cube with side a is: V = a³
D = a√3
⇒ a = D/√3

V = a³ = (D/√3)³

We have:
D = 8√2 in

V= (\frac{D}{ \sqrt{3} } )^{3} =( \frac{8 \sqrt{2} }{ \sqrt{3} } )^{3}=( \frac{8 \sqrt{2} * \sqrt{3} }{ \sqrt{3}* \sqrt{3}} )^{3} =( \frac{8 \sqrt{2*3} }{ \sqrt{3*3}} )^{3} =( \frac{8 \sqrt{6} }{ \sqrt{3^{2} }} )^{3} =( \frac{8 \sqrt{6} }{ 3} )^{3} = \\ \\ = \frac{ 8^{3} *( \sqrt{6} )^{3}}{3^{3}} = \frac{512* \sqrt{6 ^{2} }* \sqrt{6} }{27} = \frac{512*6* \sqrt{6} }{27} = 114sqrt{6}
8 0
3 years ago
Jessica, Lauren and Kimmie were paid a total of $120 for babysitting in a ratio of 2:3:5. How much less did Jessica make than Ki
Tju [1.3M]

Answer:

Jessica makes $36 less than Kimmie  

Step-by-step explanation:

Let

x -----> amount paid to Jessica

y  ----> amount paid to Lauren

z ----> amount paid to Kimmie

we know that

x+y+z=120 ------> equation A

\frac{x}{y}=\frac{2}{3}

x=\frac{2}{3}y -----> equation B

\frac{y}{z}=\frac{3}{5}

z=\frac{5}{3}y -----> equation C

substitute equation B and equation C in equation A and solve for y

\frac{2}{3}y+y+\frac{5}{3}y=120

\frac{10}{3}y=120

y=120(3)/10

y=36

<em>Find the value of x</em>

x=\frac{2}{3}(36)=24

<em>Find the value of z</em>

z=\frac{5}{3}(36)=60

therefore

The  amount paid to Jessica was $24

The amount paid to Lauren was $36

The amount paid to Kimmie was $60

To find out how much less Jessica did than Kimmie, subtract the amount paid to Jessica from the amount paid to Kimmie.

\$60-\$24=\$36

therefore

Jessica makes $36 less than Kimmie

7 0
3 years ago
Solve for x. x2 + x - 6 = 0 A. -2, -3 B. -2, 3 C. 2, -3 D. 2, 3
stiv31 [10]

Factor x^2 + x - 6

(x - 2)(x + 3) = 0

Solve for x

Ask yourself; When will (x - 2)(x + 3) equal zero?

When x - 2 = 0 or x + 3 = 0

Then solve for each of the two equations above

<em>x = 2, -3</em>

<u>Answer: C. 2, -3</u>

5 0
3 years ago
Read 2 more answers
Solve for X<br><br> B. X<br> X<br> 152
krok68 [10]

Answer:

Step-by-step explanation:

180 - 152 = 28

2x + 28 = 180

2x = 152

x = 76

3 0
3 years ago
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