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cestrela7 [59]
3 years ago
6

Find the Coordinates of the midpoint of the segment whose endpoints are H(8,2) and K(6,10)

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
5 0
I hope this helps you

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2s in 6,228 name the value
il63 [147K]

the answer would be 220

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3 years ago
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4x2 + 8x - 7 - (3x2 - X+9)​
Andreas93 [3]

Answer:

<h2>{x}^{2}  + 9x - 16</h2>

Step-by-step explanation:

4 {x}^{2}  + 8x - 7 - (3 {x}^{2}  - x + 9)

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression:

4 {x}^{2}  + 8x - 7 - 3 {x}^{2}  + x - 9

Collect like terms

4 {x}^{2}  - 3 {x}^{2}  + 8x + x - 7 - 9

{x}^{2}  + 9x - 7 - 9

Calculate

{x}^{2}  + 9x - 16

Hope this helps...

Good luck on your assignment...

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3 years ago
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If x^(2) = 64 and y^(2)= 121 what is the value of x-y?
GalinKa [24]

Step-by-step explanation:

<em>the value of x is 8</em>

8^(2) = 64

the value of y is 11

11^(2) = 121

x - y

= 8 - 11

= -3

<h3>#CMIIW</h3>

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3 years ago
What is 32 divided by 147?
liq [111]
The answer is: 0.21768707483
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What is the range of y= x + 2?
Lelu [443]

Answer:

A) all real numbers greater than or equal to 2

Domain: x\geq 0

Step-by-step explanation:

The variable in the radical <em>x </em>cannot be less than 0 as that wouldn’t be defined. So, the maximum that <em>x </em>can be is 0, and y=x+2. So, 0+2=2, and <em>y </em>is greater than or equal to 2.

Domain is x is greater than or equal to 0 because you cannot square a negative. So, it must not be less than 0. It could be 0 because square root of 0 is just 0.

7 0
3 years ago
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