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alekssr [168]
3 years ago
8

A system of equations is shown below: n = 3m + 5 n − 2m = 3 What is the solution, in the form (m, n), to the system of equations

?
a. (2,11)
b. (1,8)
c. (-2,-1)
d. (-3,-4)
Mathematics
1 answer:
marshall27 [118]3 years ago
4 0
n=3m+5 \\
n-2m=3 \\ \\
\hbox{substitute 3m+5 for n in the second equation:} \\
3m+5-2m=3 \\
m+5=3 \\
m=3-5 \\
m=-2 \\ \\
n=3m+5 \\
n=3 \times (-2)+5 \\
n=-6+5 \\
n=-1 \\ \\
(m,n)=(-2,-1)

The answer is C.
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2a - 3b = -11<br> a + 3b = 8
dlinn [17]

Answer:

b = 3 and a = -1

Step-by-step explanation:

You have your given equation:

2a - 3b = -11

a + 3b = 8

You need to find what a and b is.

To find b:

2a - 3b = -11

-2a - 6b = -16

I multiplied a + 3b = 8 by -2. When you multiply a number you have to multiply all of them. You have to choose a number that would cancel out all of a.

So now your equation would look like this when you solve for b:

2a - 3b = -11

-2a - 6b = -16

-------------------

a - 9 = -27 then you divide -9 to -27 which is 3 so b = 3.

To find a:

2a - 3b = -11

a + 3b = 8

I multiplied a + 3b = 8 by -1 and 2a - 3b = -11 by -1 as well.

Your equation will look like this when you solve for a:

-2a + 3b = 11

-1a - 3b = -8

------------------

-3a = 3 then divide -3 to 3 which is -1 so a = -1.

Check to see if you have the correct answer by plugging in the number you got for a and b into the equation and solve.

1. 2(-1) -3(3) = -11

 -2 - 9 = -11

2. -1 + 3(3) = 8

   -1 + 9 = 8

8 0
2 years ago
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