Question

A system of equations is shown below: n = 3m + 5 n − 2m = 3 What is the solution, in the form (m, n), to the system of equations?
a. (2,11)
b. (1,8)
c. (-2,-1)
d. (-3,-4)

Answer 1

$n=3m+5 \\ n-2m=3 \\ \\ \hbox{substitute 3m+5 for n in the second equation:} \\ 3m+5-2m=3 \\ m+5=3 \\ m=3-5 \\ m=-2 \\ \\ n=3m+5 \\ n=3 \times (-2)+5 \\ n=-6+5 \\ n=-1 \\ \\ (m,n)=(-2,-1)$

The answer is C.