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3 years ago

I have no clue how to do this............

Mathematics

2 answers:

PIT_PIT [208]3 years ago

6 0

Hey there! :)

The formula for finding volume of a sphere = 4/3 · π · r³

Radius = 1
1³ = 1 × 1 × 1 = 1

π = 3

3 × 1 = 3

3 × 4/3 = 12/3 = 4

The volume is 4 in³

Hope this helps :)

navik [9.2K]3 years ago

4 0

Hello!

As you can see, the volume of the sphere is V=4/3 $\pi$ r³. If $\pi$ =3, we will plug our numbers into the equation. As you can see, the radius is one.

V=4/3·3·1·³
V=4/3·3·1
V=4/3·3
V=4

I hope this helps!

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satela [25.4K]

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$y=(x-3)^{2} -25$

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The standard form of a quadratic equation is $y=ax^{2} +bx+c$

The vertex form of a quadratic equation is $y=a(x-h)^{2} +k$

The vertex of a quadratic is (h,k) which is the maximum or minimum of a quadratic equation. To find the vertex of a quadratic, you can either graph the function and find the vertex, or you can find it algebraically.

To find the h-value of the vertex, you use the following equation:

$h=\frac{-b}{2a}$

In this case, our quadratic equation is $y=x^{2} -6x-16$ . Our a-value is 1, our b-value is -6, and our c-value is -16. We will only be using the a and b values. To find the h-value, we will plug in these values into the equation shown below.

$h=\frac{-b}{2a}$ ⇒ $h=\frac{-(-6)}{2(1)}=\frac{6}{2} =3$

Now, that we found our h-value, we need to find our k-value. To find the k-value, you plug in the h-value we found into the given quadratic equation which in this case is $y=x^{2} -6x-16$

$y=x^{2} -6x-16$ ⇒ $y=(3)^{2} -6(3)-16$ ⇒ $y=9-18-16$ ⇒ $y=-25$