27. (17xyz) Taking the square root of perfect squares
1 answer:
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Answer:
2x - y - 3z = 0
Step-by-step explanation:
Since the set
{i, j} = {(1,0), (0,1)}
is a base in
and F is linear, then
<em>{F(1,0), F(0,1)} </em>
would be a base of the plane generated by F.
F(1,0) = a+b = (2i-2j+k)+(i+2j+k) = 3i+2k
F(0,1) = a+c = (2i-2j+k)+(2i+j+2k) = 4i-j+3k
Now, we just have to find the equation of the plane that contains the vectors 3i+2k and 4i-j+3k
We need a normal vector which is the cross product of 3i+2k and 4i-j+3k
(3i+2k)X(4i-j+3k) = 2i-j-3k
The equation of the plane whose normal vector is 2i-j-3k and contains the point (3,0,2) (the end of the vector F(1,0)) is given by
2(x-3) -1(y-0) -3(z-2) = 0
or what is the same
2x - y - 3z = 0
Hi there! The answer is A.
To get a proper idea of the type of function this formula represents we work out the parenthesis.
Working out the parenthesis can for instance be done using rainbow technique.
We can now see sinilarities between this function an the general function of a line in slope intercept form
The function t therefore describes a line with slope 2 and y-intercept 4. Therefore the answer is A.
To get a proper idea of the type of function this formula represents we work out the parenthesis.
Working out the parenthesis can for instance be done using rainbow technique.
We can now see sinilarities between this function an the general function of a line in slope intercept form
The function t therefore describes a line with slope 2 and y-intercept 4. Therefore the answer is A.