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Minchanka [31]
3 years ago
9

True Or false log2 8= log8 2

Mathematics
1 answer:
Alinara [238K]3 years ago
3 0
False
log base 2 of 8=3
log base 8 of 2= (1/3)

Extra Tip: log base x of y = z     ->      x^z=y 
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Solve the system by substitution
Tatiana [17]

Answer:

(x,y) = (-36,6)

Step-by-step explanation:

-6y=x

x+y=-30

x=-6y,

so -6y+y=-30

-5y=-30

y=6

x=-36

Hope this helps pls hit the crown :D

8 0
3 years ago
Find the value of x:
nadya68 [22]

Answer:

x = 3

Step-by-step explanation:

These angles are vertical angles. Vertical angles equals to on another but on the opposite side. Since they equal to another you do:

(10x + 1) = (12x - 5)

Add 5 on both sides:

10x + 6 = 12x

Subtract 10x on both sides:

6 = 2x

Divide 2 on both sides:

3 = x

6 0
3 years ago
Read 2 more answers
What is 20% of 52 (show work)
lesya692 [45]
20% of 52

Set up a proportion.

20/100 = 52/1

Divide

52*0.2 = 10.40

Final answer: 10.4
4 0
4 years ago
Read 2 more answers
Bastien, Inc. has been manufacturing small automobiles that have averaged 50 miles per gallon of gasoline in highway driving. Th
alexira [117]

Answer:

We conclude that the the manufacturer's advertising campaign is not correct.

P-value of test = 0.067.

Step-by-step explanation:

We are given that an independent testing service road-tested 36 of the automobiles. The sample showed an average of 51.5 miles per gallon. The population standard deviation is 6 miles per gallon.

We have to conduct a test to determine whether or not the manufacturer's advertising campaign is legitimate.

<u><em>Let </em></u>\mu<u><em> = population average gasoline of new small cars in highway driving.</em></u>

SO, <u>Null Hypothesis</u>, H_0 : \mu \leq 50 miles per gallon   {means that the manufacturer's advertising campaign is not correct}

<u>Alternate Hypothesis</u>, H_A : \mu > 50 miles per gallon   {means that the manufacturer's advertising campaign is correct}

The test statistics that will be used here is <u>One-sample z test</u> <u>statistics</u> as we know about the population standard deviation;

                         T.S.  = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where,  \bar X = sample average gasoline = 51.5 miles per gallon

              \sigma = population standard deviation = 6 miles per gallon

              n = sample of automobiles = 36

So, <em><u>test statistics</u></em>  =   \frac{51.5-50}{\frac{6}{\sqrt{36} } }

                               =  1.50

<em>Now at 0.05 significance level, the z table gives critical value of 1.6449 for right-tailed test. Since our test statistics is less than the critical values of z as 1.50 < 1.6449, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.</em>

<u>Also, P-value is given by the following formula;</u>

         P-value = P(Z > 1.50) = 1 - P(Z \leq 1.50)

                                            = 1 - 0.93319 = <u>0.067 or 6.7%</u>

Therefore, we conclude that the the manufacturer's advertising campaign is not correct as its new small cars average less than or equal to 50 miles per gallon in highway driving.

3 0
4 years ago
Please..............help me!!!!!!!!!!!!
Zina [86]

It is the second and third boxs


6 0
3 years ago
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