I need help on the math question look at pic

Pleaseee help asap!!! marking brainiest!!!

yan [13]

Answer:

B

Step-by-step explanation:

We can see that both functions are decreasing in [0,4]

f 868⇒ 103
g 800⇒0

868-103 =765

f decreased with 765 against 800 for g

g decreased faster

3 0

3 years ago

What is 15% of 100? Write an expression for the sequence of operations described below.

PIT_PIT [208]

Answer: 15 ; (g^5) - h

Step-by-step explanation:

To find 15% of 100, multiply 100 and 15/100. The 100's get crossed out and the answer is 15.
The expression is (g^5) - h.

7 0

3 years ago

In the past, 35% of the students at ABC University were in the Business College, 35% of the students were in the Liberal Arts Co

Vera_Pavlovna [14]

B. 0.75 is the answer for this equation

7 0

3 years ago

Evaluate the expression for the given values.<br><br> 2x + (3y + z2)<br> X = 2, y = 3, z = 4

bazaltina [42]

Answer:

29

Step-by-step explanation:

2(2)+(3(3)+(4²))

4+(9+16)

4+25

29

pls if this was h helpful pls tag brainiest

3 0

2 years ago

An auto company claims that the fuel efficiency of its sedan has been substantially improved. A consumer advocate organization w

zzz [600]

Answer:

$t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{0.983 -0}{\frac{1.685}{\sqrt{12}}}=2.021$

$df=n-1=12-1=11$

$p_v =P(t_{(11)}>2.021) =0.0342$

If we compare the the p value with the significance level provided $\alpha=0.1$ , we see that $p_v < \alpha$ , so then we can reject the null hypothesis. and there is a significant increase in the miles per gallon from 2017 to 2019 at 10% of significance.

Step-by-step explanation:

Previous concepts

A paired t-test is used to compare two population means where you have two samples in which observations in one sample can be paired with observations in the other sample. For example if we have Before-and-after observations (This problem) we can use it.

Let put some notation :

x=test value 2017 , y = test value 2019

x: 28.7 32.1 29.6 30.5 31.9 30.9 32.3 33.1 29.6 30.8 31.1 31.6

y: 31.1 32.4 31.3 33.5 31.7 32.0 31.8 29.9 31.0 32.8 32.7 33.8

Solution to the problem

The system of hypothesis for this case are:

Null hypothesis: $\mu_y- \mu_x \leq 0$

Alternative hypothesis: $\mu_y -\mu_x >0$

Because if we have an improvement we expect that the values for 2019 would be higher compared with the values for 2017

The first step is calculate the difference $d_i=y_i-x_i$ and we obtain this:

d: 2.4, 0.3, 1.7,3,-0.2, 1.1, -0.5, -3.2, 1.4, 2, 1.6, 2.2

The second step is calculate the mean difference

$\bar d= \frac{\sum_{i=1}^n d_i}{n}= \frac{11.8}{12}=0.983$

The third step would be calculate the standard deviation for the differences, and we got:

$s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =1.685$

We assume that the true difference follows a normal distribution. The 4th step is calculate the statistic given by :

$t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{0.983 -0}{\frac{1.685}{\sqrt{12}}}=2.021$

The next step is calculate the degrees of freedom given by:

$df=n-1=12-1=11$

Now we can calculate the p value, since we have a right tailed test the p value is given by:

$p_v =P(t_{(11)}>2.021) =0.0342$

If we compare the the p value with the significance level provided $\alpha=0.1$ , we see that $p_v < \alpha$ , so then we can reject the null hypothesis. and there is a significant increase in the miles per gallon from 2017 to 2019 at 10% of significance.

4 0

3 years ago

I need help on the math question look at pic​

I need help on the math question look at pic