x³ + 2x² - x - 2 < 0
x³ - x + 2x² - 2 < 0
x(x² - 1) - 2(x² - 1) < 0
(x - 2)(x² - 1) < 0
(x - 2)(x - 1)(x + 1) < 0
by chacking we get the solution
x ∈ (-∞,-1) ∪ (-1,1)
Answer:
Problem B: x = 12; m<EFG = 48
Problem C: m<G = 60; m<J = 120
Step-by-step explanation:
Problem B.
Angles EFG and IFH are vertical angles, so they are congruent.
m<EFG = m<IFH
4x = 48
x = 12
m<EFG = m<IFH = 48
Problem C.
One angle is marked a right angle, so its measure is 90 deg.
The next angle counterclockwise is marked 30 deg.
Add these two measures together, and you get 120 deg.
<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.
Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.
m<G = 180 - 120 = 60
Answer is a, 57.49.
17.42-12.60-9.62= $-4.80+62.29=57.49
Answer:
Sin = -5/13
Cos = 12/13
Tan = -5/12
Step-by-step explanation:
