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Ne4ueva [31]
3 years ago
11

Given the coordinate transformation f(x, y) = (- 2x, y) and the domain (0, 5), (8, - 1) and (- 6, 4) what is the range?

Mathematics
1 answer:
Mariana [72]3 years ago
5 0

Answer:

{(0, 5), (-16, -1), (12, 4)}

Step-by-step explanation:

Given the coordinate transformation f(x, y) = (- 2x, y) and the domain (0, 5), (8, - 1) and (- 6, 4), to get the range, we will get f(x, y) for all the domain values

For the coordinate (0,5);

f(0, 5) = (-2(0), 5)

f(0, 5) = (0, 5)

For the coordinate (8, -1);

f(8, -1) = (-2(8), -1)

f(8, -1) = (-16, -1)

For the coordinate (-6, 4);

f(-6, 4) = (-2(-6), 4)

f(0, 5) = (12, 4)

Hence the range is {(0, 5), (-16, -1), (12, 4)}

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The requirements for the hypothesis test are not met

Step-by-step explanation:

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7 0
4 years ago
Help!! What is arc HLK? Thankyou!
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5 0
3 years ago
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kicyunya [14]

Answer:

The standard deviation of given probability distribution is 0.767.

Step-by-step explanation:

We are given the following information in the question:

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Formula:

\text{Mean} = \sum X.P(x)\\= 0(0.4521) + 1(0.3970) + 2(0.1307) + 3(0.0191) + 4(0.0010)\\= 0.7197

\mu = 0.7197

Formula:

\text{Variance} = \sum (X-\mu)^2E(x)\\= (0-0.7197)^2(0.4521)+(1-0.7197)^2(0.3970)+(2-0.7197)^2(0.1307)+(3-0.7197)^2(0.0191)+(4-0.7197)^2(0.0010) \\=0.587

\text{Standard Deviation} = \sqrt{\text{Variance}}\\= \sqrt{0.587} = 0.767

The standard deviation of given probability distribution is 0.767.      

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