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Ne4ueva [31]
3 years ago
11

Given the coordinate transformation f(x, y) = (- 2x, y) and the domain (0, 5), (8, - 1) and (- 6, 4) what is the range?

Mathematics
1 answer:
Mariana [72]3 years ago
5 0

Answer:

{(0, 5), (-16, -1), (12, 4)}

Step-by-step explanation:

Given the coordinate transformation f(x, y) = (- 2x, y) and the domain (0, 5), (8, - 1) and (- 6, 4), to get the range, we will get f(x, y) for all the domain values

For the coordinate (0,5);

f(0, 5) = (-2(0), 5)

f(0, 5) = (0, 5)

For the coordinate (8, -1);

f(8, -1) = (-2(8), -1)

f(8, -1) = (-16, -1)

For the coordinate (-6, 4);

f(-6, 4) = (-2(-6), 4)

f(0, 5) = (12, 4)

Hence the range is {(0, 5), (-16, -1), (12, 4)}

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Step-by-step explanation:

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Step-by-step explanation:

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<u>Step-by-step explanation:</u>

g(x) = 3x + 2       h(x) = 5 - x²

i) h(g(x))

  h(3x + 2) = 5 - (3x + 2)²

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ii) g(h(x))

   g(5 - x²) = 3(5 - x²) + 2

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                 = 17 - 3x²

iii) h(h(x))

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                 = 5 - (25 - 10x² + x⁴)

                 = 5 - 25 + 10x² - x⁴

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