Answer:
21.21%
Step-by-step explanation:
Assume that proportion of support follows normal distribution.For resulting in defeat the proportion of support should less than 0.5.Given that the proportion of support is p= 0.52.
Sample size(n)= 402
We know that standard deviation is given as
Now by putting the values
σ=0.0249
Proportion of support follows normal distribution with mean is 0.52 and standard deviation is 0.0249
We know that 
So
Z= -0.80
So P(Z<-.80) =0.2118 from standard table.
So the probability of news paper to predict defeat is 21.21%
Answer:
143 inches
Step-by-step explanation:
Let the triangle be 
inches long.
Then the perimeter of the equilateral triangle will be 
inches.
Let the length of the square also be 
inches.
Then the perimeter is 
It was given that the perimeter of the equilateral triangle is 77 inches more than the perimeter of the square.
So we can write the relation
Also, the side of the triangle is 55 inches longer than the side of the square.
So we write 
or 
We put equation (2) into equation (1) to get;
We expand the bracket to get;
Hence the triangle is 143 inches long.
Answer:
Step-by-step explanation:
X = 26 ; y = 27
(x − y)2 = x² − 2xy + y²
(26 - 27)² = 26² - 2(26)(27) + 27²
(-1)² = 676 - 1404 + 729
1 = 1405 - 1404
1 = 1
Answer: 10.9, about 11 ft
Step-by-step explanation:
a^2 + b^2 = c^2
a^2 + (5)^2 = (12)^2
if you've read those links already, you'd know what we're doing here.
we'll move the repeating part to the left-side of the dot, by multiplying by "1" and as many zeros as needed, or 10 at some power pretty much.
on 0.13 we need 100 to get 13.13.... and on 0.1234, we need 10000 to get 1234.1234....
![\bf 0.\overline{13}~\hspace{10em}x=0.\overline{13} \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{|lll|ll} \cline{1-3} &&\\ 100\cdot 0.\overline{13}& = & 13.\overline{13}\\ 100\cdot x&& 13 + 0.\overline{13}\\ 100x&&13+x \\&&\\ \cline{1-3} \end{array}\implies \begin{array}{llll} 100x=13+x\implies 99x=13 \\\\ x=\cfrac{13}{99} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 0.\overline{1234}~\hspace{10em}x=0.\overline{1234} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%20%5Cbf%200.%5Coverline%7B13%7D~%5Chspace%7B10em%7Dx%3D0.%5Coverline%7B13%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A~%5Cdotfill%5C%5C%5C%5C%0A%5Cbegin%7Barray%7D%7B%7Clll%7Cll%7D%0A%5Ccline%7B1-3%7D%0A%26%26%5C%5C%0A100%5Ccdot%200.%5Coverline%7B13%7D%26%20%3D%20%26%2013.%5Coverline%7B13%7D%5C%5C%0A100%5Ccdot%20x%26%26%2013%20%2B%200.%5Coverline%7B13%7D%5C%5C%0A100x%26%2613%2Bx%0A%5C%5C%26%26%5C%5C%0A%5Ccline%7B1-3%7D%0A%5Cend%7Barray%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%0A100x%3D13%2Bx%5Cimplies%2099x%3D13%0A%5C%5C%5C%5C%0Ax%3D%5Ccfrac%7B13%7D%7B99%7D%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A0.%5Coverline%7B1234%7D~%5Chspace%7B10em%7Dx%3D0.%5Coverline%7B1234%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A~%5Cdotfill%20)
