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3 years ago

How to do this I don't get it

Mathematics

1 answer:

garik1379 [7]3 years ago

7 0

You split the figure into 2 pieces; then what you would do is just find the surface area or volume of the 2 separate figures and add them together! Hoped this helped!

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What is the missing step in the given proof? Statement: m∠4 = m∠15 Reason: Substitution Property of Equality Statement: m∠4 + m∠

Maru [420]

Answer:

Step-by-step explanation:

The two photos are attached for the missing information in your question.

Statement: m∠7 and m∠8 are supplementary.

Reason: Linear Pair Theorem

6 0

3 years ago

Stefan sells Jin a bicycle for $147 and a helmet for $18. The total cost for Jim is 150% of what Stefan spent originally to buy

soldi70 [24.7K]

Answer:

He spent $110.00 on both originally

Step-by-step explanation:

Add both prices too get 165

Then use the equation $\frac{150}{100}$ = $\frac{165}{x}$

cross multiply to get 150x=16500

Divide 16500 by 150 to get x alone

x= 110

4 0

3 years ago

How much pure acid should be mixed with 6 gallons of a 20% acid solution in order to get a 90% acid solution?

beks73 [17]

So, how much acid is there in 6 gallons? well is 20% acid or (20/100), so the amount of acid in it just (20/100) * 6 or 1.2, the rest is say water.

now, if we want a 90% solution, and say we add "y" gallons, how much acid is in it? well (90/100) * y, or 0.9y.

now let's add "x" gallons of pure acid, now, pure acid is just pure acid, so is 100% acid, how much acid is there in it? (100/100) * x, or 1x or just x.

we know whatever "x" and "y" amounts are, they -> x + 6 = y

and we also know that x + 1.2 = 0.9y

$\bf \begin{array}{lccclll}
&\stackrel{gallons}{acid}&\stackrel{acid~\%}{quantity}&\stackrel{acid~gallons}{quantity}\\
&------&------&------\\
\textit{pure acid}&x&1.00&x\\
\textit{20\% sol'n}&6&0.20&1.2\\
------&------&------&------\\\
mixture&y&0.90&0.9y
\end{array}
\\\\\\
\begin{cases}
x+6=\boxed{y}\\
x+1.2=0.9y\\
----------\\
x+1.2=0.9\left( \boxed{x+6} \right)
\end{cases}
\\\\\\
x+1.2=0.9x+5.4\implies x-0.9x=5.4-1.2\implies 0.1x=4.2
\\\\\\
x=\cfrac{4.2}{0.1}\implies x=\stackrel{gallons}{42}$

3 0

3 years ago

the length of a new rectangle playing field is 6 yards longer than quadruple the width. if the perimeter of the rectangle plaing

Vika [28.1K]

The length and width of a new rectangle playing field are 214 yards and 52 yards respectively.

<h3>What is the area of the rectangle?</h3>

It is defined as the area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

We have:

The length of a new rectangle playing field is 6 yards longer than quadruple the width.

Let's suppose the length is l and width is w of a rectangle:

From the problem:

l = 6 + 4w

Perimeter P = 2(l + w)

532 = 2(l + w)

Plug l = 6+4w in the above equation:

532 = 2(6 + 4w + w)

266 = 6 + 5w

260 = 5w

w = 52 yards

l = 6 +4(52) = 214 yards

Thus, the length and width of a new rectangle playing field are 214 yards and 52 yards respectively.

Learn more about the area of rectangle here:

brainly.com/question/15019502

#SPJ1

5 0

2 years ago

Plzzzz I will give you 100 points plzzz

kirza4 [7]

Answer: x < 8/9

Step-by-step explanation:

The equation is 4 * (2x +1) * 4.5 = 50, since the volume is found by multiplying the length, width, and height together, and the =50 part is because our volume can't go above 50 cubic units.

We can simplify 4 * (2x+1) * 4.5 by multiplying 4 and 4.5, which is 18, and then multiplying both 2x and 1 by 18. We get 36x + 18, and we put in the =50, so it is 36x+18=50.

Next, we can subtract 18 from both sides of the equation, giving us 36x = 32.

We then divide the equation by 36 so that we have the x by itself, and we get x = 32/36, which can be simplified to 8/9.

What we're left with is x = 8/9, meaning plugging in 8/9 for the equation would give us 50. However the problem says that the volume must be below 50, so our actual answer is x < 8/9.

7 0

3 years ago

Read 2 more answers