Question

harvey collects rare marbles. He has 125 marbles in collection 1, 36 fewer marbles in collection 2, and 53 more marbles than collection 1 in collection 3. Each display tray holds an equal number of marbles. If he uses 14 trays to to hold all of the marbles, how many marbles will he display on 3 trays? What simpler problems did you choose to solve first?

Answer 1

Collection 1, no of marbles = 125

Collection 2, no of marbles =36 fewer = 125-36 =89

Collection 3, no of marbles = 53 more =125+53 =178

Hence total marbles = 125+89+178

= 392

Given that he uses 14 trays to hold all the marables

Let us assume that he distributes equally all 392 marbles in 14 trays

Then marbles in each tray = 392/14 = 27

Thus division is used for finding out the no of marbles in a tray.

For finding out no of marbles in 3 trays, we get = 3x27 = 81 marbles

(Here direct variation is used)

Answer is 81 marbles