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3 years ago

A researcher carefully calculates the correlation coefficient and gets a value of r=1.23. What does this value mean?

Mathematics

1 answer:

Vaselesa [24]3 years ago

4 0

Answer: An error was made! All correlation coefficients: -1 ≤ r ≤ 1.

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Consider three boxes with numbered balls in them. Box A con- tains six balls numbered 1, . . . , 6. Box B contains twelve balls

murzikaleks [220]

Answer:

a) 0.73684

b) 2/3

Step-by-step explanation:

part a)

$P ( A is 1 / exactly two balls are 1) = \frac{P ( A is 1 and that exactly two balls are 1)}{P (Exactly two balls are one)}$

Using conditional probability as above:

(A,B,C)

Cases for numerator when:

P( A is 1 and exactly two balls are 1) = P( 1, not 1, 1) + P(1, 1, not 1)

= $(\frac{1}{6}* \frac{11}{12}*\frac{1}{4}) + (\frac{1}{6}*\frac{1}{12}*\frac{3}{4}) = 0.048611111$

Cases for denominator when:

P( Exactly two balls are 1) = P( 1, not 1, 1) + P(1, 1, not 1) + P(not 1, 1 , 1)

$= (\frac{1}{6}* \frac{11}{12}*\frac{1}{4}) + (\frac{1}{6}*\frac{1}{12}*\frac{3}{4}) + (\frac{5}{6}*\frac{1}{12}*\frac{1}{4})= 0.0659722222$

Hence,

$P ( A is 1 / exactly two balls are 1) = \frac{P ( A is 1 and that exactly two balls are 1)}{P (Exactly two balls are one)} = \frac{0.048611111}{0.06597222} \\\\= 0.73684$

Part b

$P ( B = 12 / A+B+C = 21) = \frac{P ( B = 12 and A+B+C = 21)}{P (A+B+C = 21)}$

Cases for denominator when:

P ( A + B + C = 21) = P(5,12,4) + P(6,11,4) + P(6,12,3)

$= 3*P(5,12,4 ) =3* \frac{1}{6}*\frac{1}{12}*\frac{1}{4}\\\\= \frac{1}{96}$

Cases for numerator when:

P (B = 12 & A + B + C = 21) = P(5,12,4) + P(6,12,3)

$= 2*P(5,12,4 ) =2* \frac{1}{6}*\frac{1}{12}*\frac{1}{4}\\\\= \frac{1}{144}$

Hence,

$P ( B = 12 / A+B+C = 21) = \frac{\frac{1}{144} }{\frac{1}{96} }\\\\= \frac{2}{3}$

4 0

3 years ago

A pawn shop buys a pair of sunglasses for $20 and marks up the cost 15% to make a profit. What is the selling price?

Tema [17]

Well i do believe the new price would be $23.00. hope this helps.

8 0

2 years ago

BRAINLIEST!!!! Identify the equation of the translated graph in general form

RUDIKE [14]

Answer:

Hyperbola:

$x^2-y^2-8x+6y-1=0$

Step-by-step explanation:

the given hyperbola has equation:

$x^2-y^2=8$

This is an equation of a hyperbola centered at the origin.

This hyperbola is translated so its center is now at T(4,3)

$(x-4)^2-(y-3)^2=8$

We expand to get:

$x^2-8x+16-(y^2-6y+9)=8$

$x^2-8x+16-y^2+6y-9=8$

$x^2-8x-y^2+6y+7=8$

$x^2-8x-y^2+6y+7-8=0$

$x^2-y^2-8x+6y-1=0$

8 0

3 years ago

Read 2 more answers

HELP ASAP!!!!!!!!!!!!

timofeeve [1]

Answer:40 yd ^2

Step-by-step explanation:

multiply the parts

BRAINLEST PLEASE PLEASE PLEASE

3 0

3 years ago

Read 2 more answers

To summarize what you have learned in this lesson, answer the questions below:

DerKrebs [107]

Answer:

sorry i don't know the answer:(

4 0

3 years ago