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Lana71 [14]
4 years ago
13

Which is the correct statement 3/32< 5/32, 3/32>5/32, 3/32=5/32

Mathematics
1 answer:
NISA [10]4 years ago
8 0
The first statement 3/32<5/322 would be correct
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Help please I am in dire need
DiKsa [7]

Answer:

Answer is d=9t.

Step-by-Step:

4.5/.5=9

6.75/.75=9

13.5/1.5=9

7 0
3 years ago
Read 2 more answers
Edwin needs to buy a car, a truck, and a motorcycle for his shipping business. He wants the car to be red or yellow; the truck t
Amanda [17]
We can solve problems like this using multiplication rules. Since the order of colors and combinations does not matter, we can multiply all  values in any order we so choose. In this case, our values are colors and vehicles:

Car: Red, Yellow
Truck: Black, White, Silver
Motorcycle: Green, Blue, Orange

We have 2 options with a car, 3 options with a truck, and 3 options with a motorcycle. Since he wants one of each, we will multiply all of the color options together: 

2 x 3 x 3

= 18

Edwin has 18 different combination of vehicles to choose from.
8 0
3 years ago
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PLZ HELP QUICK Which property explains why these two expressions are equal - the commutative, the associative, or distributive p
r-ruslan [8.4K]

Answer:

I think it's commutative. ;-;

Step-by-step explanation:

4 0
3 years ago
F(n)=4n <br> g(n)=n2+2n <br> find f(g(-6))
ELEN [110]

Answer:

When f(n) = 4n and g(n) = n² + 2n, f(g(-6)) = 96.

Step-by-step explanation:

To evaluate f(g(-6)), first find g(-6).

g(n) = n² + 2n

Substitute value.

g(-6) = (-6)² + 2(-6)

Square -6. Remember that (-x)² = x²

g(-6) = 36 + 2(-6)

Multiply 2 and -6.

g(-6) = 36 - 12

Subtract 12 from 36.

g(-6) = 24.

Now knowing this, substitute that value into f(n).

f(g(-6)) = f(24)

f(n) = 4n

Substitute value.

f(24) = 4(24)

Multiply 4 and 24.

f(24) = 96.

8 0
3 years ago
For what values of a is the distance between P(a,3) and Q(5,2a) greater than √26
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P(a,3)\ \ \ Q(5,2a)\\\\ PQ=\sqrt{(x_Q-x_P)^2+(y_Q-y_P)^2}\\\\ PQ>\sqrt{26}\\\\\sqrt{(5-a)^2+(2a-3)^2}>\sqrt{26}\\\\\sqrt{25-10a+a^2+4a^2-12a+9}>\sqrt{26}\\\\\sqrt{5a^2-22a+34}>\sqrt{26}\ \ |^{2}\\\\&#10;5a^2-22a+34=26\ \ \ |Subtract\ 26\\\\&#10;5a^2-22a+8=0\ \ \ |Factoring\\\\(a-4)(5a-2)=0\\\\&#10;a=4\ \  or\ \  5a=2\\&#10;a=4\ \ or\ \ a=\frac{2}{5}
6 0
3 years ago
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