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Lana71 [14]
3 years ago
13

Which is the correct statement 3/32< 5/32, 3/32>5/32, 3/32=5/32

Mathematics
1 answer:
NISA [10]3 years ago
8 0
The first statement 3/32<5/322 would be correct
You might be interested in
Select the correct answer.
steposvetlana [31]

Answer:

C. 7

49 square rooted would be 7 and the 4 in (x+4) would be negative and not positive like the answer shows.

4 0
2 years ago
Which sentence is an example of the distributive property
Marrrta [24]

The distributive property of multiplication is a very useful property that lets you simplify expressions in which you are multiplying a number by a sum or difference. The property states that the product of a sum or difference, such as 6(5 – 2), is equal to the sum or difference of the products – in this case, 6(5) – 6(2).

 

Remember that there are several ways to write multiplication. 3 x 6 = 3(6) = 3 • 6.

3 • (2 + 4) = 3 • 6 = 18.

 

Distributive Property of Multiplication over Addition

 

<span>The distributive property of multiplication over addition can be used when you multiply a number by a sum. For example, suppose you want to multiply 3 by the sum of 10 + 2.</span>

 

3(10 + 2) = ?

 

According to this property, you can add the numbers and then multiply by 3.

<span>3(10 + 2) = 3(12) = 36. Or, you can first multiply each addend by the 3. (This is called distributing the 3.) Then, you can add the products.</span>

The multiplication of 3(10) and 3(2) will each be done before you add.

3(10) + 3(2) = 30 + 6 = 36. Note that the answer is the same as before.

 

You probably use this property without knowing that you are using it. When a group (let’s say 5 of you) order food, and order the same thing (let’s say you each order a hamburger for $3 each and a coke for $1 each), you can compute the bill (without tax) in two ways. You can figure out how much each of you needs to pay and multiply the sum times the number of you. So, you each pay (3 + 1) and then multiply times 5. That’s 5(3 + 1) = 5(4) = 20. Or, you can figure out how much the 5 hamburgers will cost and the 5 cokes and then find the total. That’s 5(3) + 5(1) = 15 + 5 = 20. Either way, the answer is the same, $20.

 

The two methods are represented by the equations below. On the left side, we add 10 and 2, and then multiply by 3. The expression is rewritten using the distributive property on the right side, where we distribute the 3, then multiply each by 3 and add the results. Notice that the result is the same in each case.

 

7 0
3 years ago
Read 2 more answers
Divide and simplify 6 divided by 2 2/3
Ilya [14]
6/2
3*2/3
12
Is the answer...
7 0
2 years ago
Need help plzz! will give best answer brainliest!!!
german

Second graph because there are positive

and functioning

7 0
2 years ago
Read 2 more answers
Find an equation of the tangent to the curve at the given point by both eliminating the parameter and without eliminating the pa
konstantin123 [22]

Answer:

y=2x-8

Step-by-step explanation:

The given parametric equation is;

x=6+ln(t),y=t^2+3

<h3><u>BY ELIMINATING THE PARAMETER</u></h3>

To eliminate the parameter we make t the subject in one equation and put it inside the other.

We make t the subject in x=6+ln(t) because it is easier.

\Rightarrow x-6=ln(t)

\Rightarrow {e}^{x-6}=e^{ln(t)}

\Rightarrow {e}^{x-6}=t

Or

t={e}^{x-6}

We now substitute this into y=t^2+3.

This gives us;

y=(e^{x-6})^2+3.

\Rightarrow y=e^{2(x-6)}+3.

We have now eliminated the parameter.

The equation of the tangent at (6,4) is given by;

y-y_1=m(x-x_1)

where the gradient function is given by;

\frac{dy}{dx}=2e^{2(x-6)}

We substitute x=6 into the gradient function to obtain the gradient.

\Rightarrow m=2e^{2(6-6)}

\Rightarrow m=2e^0

\Rightarrow m=2

The equation of the tangent becomes

y-4=2(x-6)

We simplify to obtain

y=2x-12+4

y=2x-8

<h3><u>WITHOUT ELIMINATING THE PARAMETER</u></h3>

The given parametric equation is;

x=6+ln(t),y=t^2+3

For x=6+ln(t)

\frac{dx}{dt}=\frac{1}{t}

For y=t^2+3

\frac{dy}{dt}=2t

The slope is given by;

\frac{dy}{dx}=\frac{\frac{dy}{dt} }{\frac{dx}{dt} }

\frac{dy}{dx}=\frac{2t }{\frac{1}{t} }

\frac{dy}{dx}=2t^2

At the point, (6,4), we plug in any of the values into the parametric equation and find the corresponding value for t.

Notice that

When x=6, 6=6+\ln(t)

6-6=\ln(t)

0=\ln(t)

e^0=e^\ln(t)

1=t

when y=4, 4=t^2+3

4-3=t^2

1=t^2

t=\pm1

But the slope is the same when we plug in any of these values for t.

\frac{dy}{dx}=2(\pm1)^2=2

The equation of the tangent becomes

y-4=2(x-6)

We simplify to obtain

y=2x-12+4

y=2x-8

7 0
2 years ago
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