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2 years ago

The legs of a right triangle have the following measurements: 5 and 10 inches. What is the length of the hypotenuse??

Mathematics

1 answer:

RideAnS [48]2 years ago

7 0

Answer:

$5\sqrt{5}$

Step-by-step explanation:

1. $5^2 + 10^2 = c^2$

2. $125 = c^2$

3. $c=5\sqrt{5}$

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$\bf \textit{Cofunction Identities}
\\ \quad \\
sin\left(\frac{\pi}{2}-{{ \theta}}\right)=cos({{ \theta}})\qquad 
\boxed{cos\left(\frac{\pi}{2}-{{ \theta}}\right)=sin({{ \theta}})}
\\ \quad \\ \quad \\
tan\left(\frac{\pi}{2}-{{ \theta}}\right)=cot({{ \theta}})\qquad 
cot\left(\frac{\pi}{2}-{{ \theta}}\right)=tan({{ \theta}})
\\ \quad \\ \quad \\
sec\left(\frac{\pi}{2}-{{ \theta}}\right)=csc({{ \theta}})\qquad 
csc\left(\frac{\pi}{2}-{{ \theta}}\right)=sec({{ \theta}})$

$\bf \\\\
-------------------------------\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta )
\\\\\\
\boxed{cos(\theta )=\sqrt{1-sin^2(\theta )}}$

$\bf \\\\
-------------------------------\\\\
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sin(x)\cdot \cfrac{sin(x)}{cos(x)}\implies sin(x)tan(x)$

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