Question

Simplify the radical expression.

Answer 1

$\\\dfrac{ \sqrt{6}}{ \sqrt{2n} } \\ \\ = \dfrac{ \sqrt{3 \times 2}}{ \sqrt{2 \times n} } \\ \\ = \dfrac{ \sqrt{3} \times \sqrt{2} }{ \sqrt{2} \times \sqrt{n} } \\ \\ = \dfrac{ \sqrt{3} }{ \sqrt{n}} \\ \\ = \sqrt{ \dfrac{3}{n}}$