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Svetllana [295]
3 years ago
13

HELLO! SOS!!! PLEASE HELP ME!!! THANK YOU SO MUCH!!! WILL MARK BRAINLIEST!! WORTH 25 PTS!! THANK YOU AGAIN!!

Mathematics
2 answers:
Rasek [7]3 years ago
5 0

Answer:

16.5

Step-by-step explanation:

tan(70) = opposite/adjacent

tan(70) = x/6

x = 6tan(70)

x = 16.4848645167

lozanna [386]3 years ago
4 0

Answer:

16.5 =x

Step-by-step explanation:

Since this is a right triangle, we can us trig functions

tan theta = opp side / adjacent

tan 70 = x /6

Multiply each side by 6

6 tan 70 = x

16.48486452 =x

To the nearest tenth

16.5 =x

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Factor x^2-2x-4 PLEASE ANSWER QUICKLY!!! I WILL GIVE POINTS!!! DBA IS TODAY!!!!
Thepotemich [5.8K]

To factor x²-2x-4, you are looking to answer three questions.

1) What pair of numbers multiplies to 4?

2) What pair of numbers multiplies to 1?

3) Do these pairs when multiplied together, add/subtract to the middle term?

To answer (1), our pairs are 2 and 2, 4 and 1. Since there's a negative with 4 at the end (from question one), the signs will be opposite.

To answer (2), only pair multiplies to 1 - 1 and 1. Let's try both pairs from 1.

(x-4)(x+1) The middle term here is -3x. Nope.

(x-1)(x+4). The middle term here is 3x. Nope.

(x-2)(x+2) The middle term is 0x (or no middle term). Nope.

So x²-2x-4 does not factor.

4 0
3 years ago
9. Factorize: 6x2 - 19x + 14.​
Stella [2.4K]

Answer:

Step-by-step explanation:

Here, we want to factor the given polynomial

We have this as;

6x^2 - 19x + 14

= 6x^2 -12x-7x + 14

= 6x(x-2) -7(x-2)

= (6x-7)(x-2)

6x^2-19x + 14 = (6x-7)(x-2)

4 0
3 years ago
Twenty five heat lamps are connected in a greenhouse so, that when one lamp fails, another takes over immediately (only one lamp
olga55 [171]

Answer:

P = 0.006

Step-by-step explanation:

Given

n = 25 Lamps

each with mean lifetime of 50 hours and standard deviation (SD) of 4 hours

Find probability that the lamp will be burning at end of 1300 hours period.

As we are not given that exact lamp, it means we have to find the probability where any of the lamp burning at the end of 1300 hours, So we have

Suppose i represents lamps

P (∑i from 1 to 25 (X_i > 1300)) = 1300

= P(X^{'}> \frac{1300}{25})                  where X^{'} represents mean time of a single lamp

= P (Z> \frac{52-50}{\frac{1}{\sqrt{25}}})                Z is the standard normal distribution which can be found by using the formula

Z = Mean Time (X^{'}) - Life time of each Lamp (50 hours)/ (SD/\sqrt{n})

Z = (52-50)/(4/\sqrt{25}) = 2.5

Now, P(Z>2.5) = 0.006 using the standard normal distribution table

Probability that a lamp will be burning at the end of 1300 hours period is 0.006

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3 years ago
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Answer:

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