All categories

3 years ago

In Europe, there are a total of 288 spoken languages. Of those, 121 are endangered. What percent of Europe’s languages is that?

2 answers:

8 0

$\text{Hello there!}\\\\\text{We know that there are a total of 288 languages}\\\\\text{121 of them are endangered}\\\\\text{So, we have to find the percentage of 121 in 288}\\\\\text{Make your expression}\\\\121\cdot100/288\\\\\text{Solve:}\\\\121\cdot100/288\\\\12100/288\\\\\boxed{42.01}$

pav-90 [236]3 years ago

3 0

Answer:

42.01 %.

Step-by-step explanation:

That is 121 * 100 / 288

= 42.01 %.

You might be interested in

Para decorar una pared se disponen de tiras de papel azules de 15 cm, verdes de 20 cm, y rojas de 25 cm. En la pared se quiere a

den301095 [7]

Answer:

a) Smallest line that can be made with each color = 300 cm

b) Total strips should be used = 47 strips

c) Total strips used of blue color = 20

Total strips used of green color = 15

Total strips used of red color = 12

Step-by-step explanation:

Given - To decorate a wall, there are 15 cm blue, 20 cm green, and 25 cm red strips of paper. On the wall you want to build three lines of the same size, one of each color and without cutting any strip.

To find - a) How long is the smallest line that can be made with each color?

b) How many strips should be used?

c) How many of each color?

Proof -

For the smallest line that can be made with each color, we just have to find the lcm (least common multiple) of the 3 srtips.

Firstly,

Decompose the 3 strips to its prime factors , we get

15 = 3×5

20 = 2²×5

25 = 5²

So,

The Lcm(15, 20, 25) = 3×2²×5² = 3×4×25 = 300

∴ we get

Smallest line that can be made with each color = 300 cm

Now,

Total strips used = 300 cm

Strips used by 15 cm blue = $\frac{300}{15}$ = 20 strips

Strips used by 20 cm green = $\frac{300}{20}$ = 15 strips

Strips used by 25 cm red = $\frac{300}{25}$ = 12 strips

So,

Total strips should be used = 20 + 15 + 12 = 47 strips

Total strips used of blue color = 20

Total strips used of green color = 15

Total strips used of red color = 12

6 0

3 years ago

A student solved the following problem and made an error: Triangles ABC and DEF. Angles A and F are congruent and measure 135 de

dmitriy555 [2]

We have that
triangle ABC coordinates
A (0,2) B(2,4) C(0,0)

triangle DEF coordinates
D (2,0) E ( 4,4) F (4,2)

using a graph tool
see the attached figure

therefore

Line 1 Segment AC equals 2. Segment FE equals 2. Segment AC is congruent to segment FE
so
Segment AC equals 2-------> is correct
Segment FE equals 2-----> is correct
Segment AC is congruent to segment FE------> is correct

Line 2 ∠A ≅ ∠F------> is correct

Line 3 Length of segment AB. A (0, 2) B (2, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub 1 squared, d equals square root of quantity 0 minus 2 all squared plus quantity 2 minus 4 all squared, d equals square root of negative 2 squared plus negative 2 squared, d equals square root of 4 plus 4, d equals square root of 8 segment AB = 2.83

find the distance AB
d=√[(4-2)²+(2-0)²]--------> d=√[4+4]-----> d=√8-----> d=2.83
AB=2.83
so
Line 3 is correct

Line 4 Length of segment DE. D (2, 0) E (4, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub squared, d equals square root of quantity 2 minus 4 all squared plus quantity 0 minus 4 all squared, d equals square root of negative 2 squared plus negative 4 squared, d equals square root of 4 plus 16, then d equals square root of 20 segment DE = 4.47

find the distance DE
d=√[(4-0)²+(4-2)²]--------> d=√[16+4]-----> d=√20-----> d=4.47
DE=4.47
so
Line 4------> is correct

Line 5 segment AB is congruent with segment DE
AB is not congruent with DE
so
Line 5 is not correct

therefore

the answer is
the student make the first mistake in line 5