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3 years ago

Can someone help please?!!! im in a hurry :(

Mathematics

2 answers:

Alina [70]3 years ago

8 0

I'm pretty sure it would be 2 and 90, let me know if I'm wrong.

Firdavs [7]3 years ago

5 0

Answer:

2, 90

Step-by-step explanation:

Divide 54 by 3 to get how many licks are needed for ONE lollipop. Once you figure how many licks are needed for ONE, you can figure out how many it takes for any amount of lollipops.

54 licks / 3 lollipops = 18 licks / 1 lollipop

Divide 36 by 18 and multiply the quotient by 18 to find the number of lollipops 36 licks takes.

36 licks / 18 licks = 2 lollipops (this is your first answer)

Now multiply 18 by 5 like so: 18 * 5 = 90 (this is your second answer)

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The function h(t) = 150 – 9t represents the height of a ball dropped from 150 feet after t seconds. What will the height of the

Alekssandra [29.7K]

After 1.4 seconds, t = 1.4.
h(t) = 150 - 9(1.4)
Multiply 9 by 1.4 to get 12.6.
h(t) = 150 - 12.6
Subtract 12.6 from 150 to get 137.4.
h(t) = 137.4.
The height of the ball would be 137.4 after 1.4 seconds.
Hope this helps!

3 0

3 years ago

I am giving away my points bc I don't like this website

LiRa [457]

Thanks !!!!!!!!!!!!!

4 0

3 years ago

There is a group of student,1/3 are in elementary ,1/2 are in middle school and 15 are in high school. How many are in the group

OverLord2011 [107]

1/2 + 1/3 = 3/6 + 2/6 = 5/6
we have 5/6 so 15 is 1/6 of the entire group
15 × 6 = 90

7 0

3 years ago

PLS HELP ME!!!!!!!!! I WILL MARK YOU!!!!!

Nikitich [7]

Answer:

7.92

Step-by-step explanation:

Given

c² + 0.1c - 24 ← substitute c = - 5.7 into the expression

= (- 5.7)² + 0.1(- 5.7) - 24

= 32.49 - 0.57 - 24

= 31.92 - 24

= 7.92

4 0

3 years ago

The following histogram presents the amounts of silver (in parts per million) found in a sample of rocks. One rectangle from the

gladu [14]

Answer:

The height of the missing rectangle is 0.15

Explanation:

The image attached has the mentioned histogram.

Such histogram presents the relative frequencies for the clases [0,1], [1,2],[2,3], [4,5], and [5,6] Silver in ppm.

Only the rectangle for the class [3,4] is missing.

The height of each rectangle is the relative frequency of the corresponding class.

The relative frequencies must add 1, because each relative frequency is calculated dividing the absolute class frequency by the total number in the sample; hence, the sum of all the relative frequencies is equal to the total absolute class frequencies divided by the same number, yielding 1.

In consequence, you can sum all the known relative frequencies and subtract from 1 to get the missing relative frequency, which is the height of the missing rectangle.

1. Sum of the known relative frequencies:

0.2 + 0.3 + 0.15 + 0.1 + 0.1 = 0.85

2. Missing frequency:

1 - 0.85 = 0.15

3. Conclusion:

The height of the missing rectangle is 0.15

4 0

3 years ago