Let the first page = x
The second page would be x + 1
Add them together to equal 347
X + x + 1 = 347
Combine like terms:
2x + 1 = 347
Subtract 1 from both sides
2x = 346
Divide both sides by 2:
X = 173
The smaller page number is 173
The larger page number is 174
Answer:
0.0071 & 0.004
Step-by-step explanation:
Total number of vowels 'V'=5
total number of alphabets= 26
therefore, P(V)=5/26
P(3 V's with replacement)= (5/26)³
=0.0071
P(3 V's without replacement)=(5/26)(4/25)(3/23)
=0.004
The first event is independent
The second event is dependent
X intercept (2,0)
Y intercept (0,-1)
Answer:
10.20% probability that a randomly chosen book is more than 20.2 mm thick
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
250 sheets, each sheet has mean 0.08 mm and standard deviation 0.01 mm.
So for the book.

What is the probability that a randomly chosen book is more than 20.2 mm thick (not including the covers)
This is 1 subtracted by the pvalue of Z when X = 20.2. So



has a pvalue of 0.8980
1 - 0.8980 = 0.1020
10.20% probability that a randomly chosen book is more than 20.2 mm thick
Answer:
x=24
Step-by-step explanation:
x/2+3=15
-3 both sides
x/2=15−3
15-3=12
x/2=12
12*2=24
x=24