Answer:
I wish I knew this maybe use the brainy scanner it could help you or google.
Answer:
6.36l
Step-by-step explanation:
We compute first the volume:
V=pi×h/3×(R²+r²+rR), where h=20cm is the height, R=24/2=12cm is the top radius, r=16/2=8cm is the bottom radius.
We get: V=pi×20/3(12²+8²+12×8)=
20×pi/3(144+64+96)cm³
V=20×pi/3×304=6363.73cm³
In dm³ we have (divide by 1000) V=6.36dm³
By definition, 1dm³=1l, so the capacity is 6.36l
Notice the picture,
recall your SOH, CAH, TOA
you have,
opposite side, 165
adjacent side, 50
and the angle
that means, we'll need Mrs. tangent
thus
![\bf tan(\theta)=\cfrac{opposite}{adjacent}\implies tan(\theta)=\cfrac{165}{50} \\ \quad \\ tan^{-1}\left[ tan(\theta) \right]=tan^{-1}\left[ \cfrac{165}{50} \right] \\ \quad \\ \theta=tan^{-1}\left[ \cfrac{165}{50}\right] \\ \uparrow \\ \textit{angle of elevation}\iff\textit{angle of depression}](https://tex.z-dn.net/?f=%5Cbf%20tan%28%5Ctheta%29%3D%5Ccfrac%7Bopposite%7D%7Badjacent%7D%5Cimplies%20tan%28%5Ctheta%29%3D%5Ccfrac%7B165%7D%7B50%7D%0A%5C%5C%20%5Cquad%20%5C%5C%0A%20tan%5E%7B-1%7D%5Cleft%5B%20tan%28%5Ctheta%29%20%5Cright%5D%3Dtan%5E%7B-1%7D%5Cleft%5B%20%5Ccfrac%7B165%7D%7B50%7D%20%5Cright%5D%0A%5C%5C%20%5Cquad%20%5C%5C%0A%5Ctheta%3Dtan%5E%7B-1%7D%5Cleft%5B%20%5Ccfrac%7B165%7D%7B50%7D%5Cright%5D%0A%5C%5C%20%5Cuparrow%20%20%5C%5C%0A%20%5Ctextit%7Bangle%20of%20elevation%7D%5Ciff%5Ctextit%7Bangle%20of%20depression%7D)
So the ration is 1 to 5 since it's one foot every 5 seconds. So for every 5 seconds, add 1 foot.
For example: in 45 seconds, it would travel 7 feet.
But in this Scenario, the timer starts after 5 feet so just add 5
Ex. in 45 seconds, it would have traveled 12 feet since we added the 5 feet that we started with to the 7 other feet it traveled.
Idk If this will help very much but I hope it does.
