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3 years ago

8

If a population is known to be normally distributed, what can be said of the sample distribution of the sample mean drawn from t

his population?

1 answer:

belka [17]3 years ago

8 0

That they are diffrent type of numbers

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PLEASE HELP WILL GIVE BRAINLIEST AND 30 POINTS!!!!!

garik1379 [7]

Answer:

Step-by-step explanation:

If the price is supposed to be dropping with each year, maybe your year/price chart would reflect that. Seems to me that the price rose between 2015 and 2016 and even by 2017 the value was still higher than it was in 2015.

I have no way of knowing how to fix this.

Let's ASSUME that the 2015 price was $71,445 and that the 2016 and 2017 prices are valid.

the decrease between 2015 and 2016 is (71445 - 68640) / 71445 = 0.03926

or 3.926%

the decrease between 2016 and 2017 is (68640 - 65945)/68640 = 0.03926

or 3.926%

so the price each year after new is

p = 71445(1 - 0.03926)ⁿ

or

71445(0.96074)ⁿ

where n is the number of years.

To get the monthly version, we divide the decrease by 12

p = 71445(1 - 0.03926/12)ˣ

or

p = 71445(1 - 0.00327)ˣ

or

p = 71445(0.99673)ˣ

where x is the number of months since new.

This may not be your exact answer, but the same method can be used if you get real numbers.

8 0

3 years ago

Karina bought 4 packages of the type of gum shown.

Radda [10]

Answer:

Step-by-step explanation:4n+3=60

5 0

3 years ago

Prove :<br>sin²θ + cos²θ = 1<br><br><br>thankyou ~

Gnom [1K]

Answer:

See below

Step-by-step explanation:

Here we need to prove that ,

$\sf\longrightarrow sin^2\theta + cos^2\theta = 1$

Imagine a right angled triangle with one of its acute angle as $\theta$ .

The side opposite to this angle will be perpendicular .
Also we know that ,

$\sf\longrightarrow sin\theta =\dfrac{p}{h} \\$

$\sf\longrightarrow cos\theta =\dfrac{b}{h}$

And by Pythagoras theorem ,

$\sf\longrightarrow h^2 = p^2+b^2 \dots (i)$

Where the symbols have their usual meaning.

Now , taking LHS ,

$\sf\longrightarrow sin^2\theta +cos^2\theta$

Substituting the respective values,

$\sf\longrightarrow \bigg(\dfrac{p}{h}\bigg)^2+\bigg(\dfrac{b}{h}\bigg)^2\\$

$\sf\longrightarrow \dfrac{p^2}{h^2}+\dfrac{b^2}{h^2}\\$

$\sf\longrightarrow \dfrac{p^2+b^2}{h^2}$

From equation (i) ,

$\sf\longrightarrow\cancel{ \dfrac{h^2}{h^2}}\\$

$\sf\longrightarrow \bf 1 = RHS$

Since LHS = RHS ,

Hence Proved !

I hope this helps.

5 0

2 years ago

2. Given: mZABD = rº and mZACB = yo

Ede4ka [16]

Step-by-step explanation:

the angle ABC = 180 - x, as ABD and ABC are complementary angles on top of the bottom line : all angles around a point on one side of a line are always adding up to 180 degrees.

but because we also know that the sum of all angles in a triangle is 180 degrees too, we can say

180 = ACB + ABC + CAB

180 = y + 180 - x + CAB

0 = y - x + CAB

x = y + CAB

x - y = CAB

therefore, the second answer option is correct.

3 0

2 years ago

Lura’s chocolate bar is 71% cacoa. If the weight of the chocolate bar is 58 grams, how many grams of cocoa does it contain? Roun

gtnhenbr [62]

58*0.71= around 41.2 grams of coco. This is because we can multiply to get this.

Please like and brainiest if correct!

4 0

2 years ago