Answer:
Step-by-step explanation
We have given that equation of line a+4b=0
⇒4b= -a
⇒
slope of line =
⇒ is negative therefore it lies into 4th quadrant
By, Pythagoras theorem
by putting value of P= -1 & B=4
the value of
with the given condition
i.e. ∈ (3π/2, 2π)
now,
Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
━═━═━═━═━═━═━═━═━━═━═━═━═━═━